当任何命令（包括非简单命令）失败时退出的 Bash 脚本
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Bash script to exit when any command (including non-simple commands) fail
提问by Alexander Collins
I have a script
我有一个脚本
#! /bin/sh
set -eux
command_a
command_b | command_c
while [ true ]; do
command_d
done
I'd like this to fail when any command fails. If command_afails, the script fails, but if command_bor command_d(not sure about command_c) fail, the script carries on.
当任何命令失败时，我希望它失败。如果command_a失败，脚本将失败，但如果command_b或command_d（不确定command_c）失败，脚本将继续执行。
采纳答案by Ashutosh Bharti
This should not happen if you are using set -eux, may be I can tell better if I knew the actual command.
One way to achieve exiting can be to use ||
如果您正在使用set -eux，则不应发生这种情况，如果我知道实际命令，我可能会说得更好。实现退出的一种方法是使用||
while [ true ]; do
command_d || exit 1
done
a || bmeans "do a (completely). If it didn't succeed, do b"
a || b意思是“做a（完全）。如果没有成功，做b”
Also, you should use set -euxo pipefail
另外，你应该使用 set -euxo pipefail
Refer this: https://vaneyckt.io/posts/safer_bash_scripts_with_set_euxo_pipefail/
请参阅：https: //vaneyckt.io/posts/safer_bash_scripts_with_set_euxo_pipefail/
