Java 如何将 JSON 解析为字符串列表?

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时间:2020-08-13 18:36:38  来源:igfitidea点击:

How to parse JSON to list of strings?

javaHymanson

提问by Flavio

I have a json file.

我有一个 json 文件。

{
    "data" : [
        "my/path/old",
        "my/path/new"
    ]
}

I need to conver it to ArrayList of String. How to do it using Hymanson library?

我需要将它转换为 String 的 ArrayList。如何使用Hyman逊图书馆做到这一点?

UPD:

更新:

My code:

我的代码:

Gson gson = new Gson();        
JsonReader reader = new JsonReader(new InputStreamReader(FileReader.class.getResourceAsStream(file)));

List<String> list = (ArrayList) gson.fromJson(reader, ArrayList.class);

for (String s : list) {
    System.out.println(s);
}

And my exception:

而我的例外:

Exception in thread "main" com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Expected value at line 1 column 1

My new update

我的新更新

UPD2:

UPD2:

Gson gson = new Gson();
Type list = new TypeToken<List<String>>(){}.getType();
JsonReader reader = new JsonReader(new InputStreamReader(FileReader.class.getResourceAsStream(file)));
List<String> s = gson.fromJson(reader, list);
System.out.println(s);

采纳答案by Sotirios Delimanolis

You've tagged Hymanson but are using Gson in your example. I'm going to go with Hymanson

您已经标记了 Hymanson,但在您的示例中使用了 Gson。我要和Hyman逊一起去

String json = "{\"data\":[\"my/path/old\",\"my/path/new\"]}"; // or wherever you're getting it from

Create your ObjectMapper

创建您的 ObjectMapper

ObjectMapper mapper = new ObjectMapper();

Read the JSON String as a tree. Since we know it's an object, you can cast the JsonNodeto an ObjectNode.

将 JSON 字符串作为树读取。由于我们知道它是一个对象,因此您可以将JsonNode转换为ObjectNode

ObjectNode node = (ObjectNode)mapper.readTree(json);

Get the JsonNodenamed data

获取JsonNode命名data

JsonNode arrayNode = node.get("data");

Parse it into an ArrayList<String>

将其解析为 ArrayList<String>

ArrayList<String> data = mapper.readValue(arrayNode.traverse(), new TypeReference<ArrayList<String>>(){});

Printing it

打印它

System.out.println(data);

gives

[my/path/old, my/path/new]