jQuery & Ajax：ReferenceError: ajax 未定义
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jQuery & Ajax: ReferenceError: ajax is not defined
提问by user2807746
I get a
我得到一个
ReferenceError: ajax is not defined
参考错误：ajax 未定义
error in browser console when I try to make an ajax call.
当我尝试进行 ajax 调用时，浏览器控制台中出现错误。
I'm pretty sure I properly loaded the jQuery library, therefore I don't understand how can the $.ajax function not be defined.
我很确定我正确加载了 jQuery 库，因此我不明白如何不定义 $.ajax 函数。
Here is the HTML (without irrelevent css and markup):
这是 HTML（没有无关的 css 和标记）：
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="js/script.js"></script>
</head>
<body>
<div>
<a class="getUsersA">Get users</a>
<div id="gridD"></div>
</div>
</body>
</html>
Here is the script.js file:
这是 script.js 文件：
$(document).ready(function() {
$(".getUsersA").click(function() {
$.ajax({
url:ajax/getUsers.php,
type:POST,
data:({
id:0
}),
success:function(results) {
$("#gridD").html(results);
}
});
});
});
Thank you for any help!
感谢您的任何帮助！
回答by karthikr
You need to wrap ajax/getUsers.php,in quotes. or else it would look for a local variable ajaxrather than treating it as a string.
你需要ajax/getUsers.php,用引号括起来。否则它会寻找一个局部变量ajax而不是将其视为字符串。
url: "ajax/getUsers.php",
Something like this:
像这样的东西：
$.ajax({
url: 'ajax/getUsers.php',
type: 'POST',
data:({
id: 0
}),
success:function(results) {
$("#gridD").html(results);
}
});
回答by Curt
You have a syntax error on this line:
您在这一行有语法错误：
url:ajax/getUsers.php,
Change this to:
将此更改为：
url:"ajax/getUsers.php",
回答by Anthony Grist
You're supposed to be passing a string (or a variable containing a string) as the urloption, but you're instead doing:
您应该传递一个字符串（或包含字符串的变量）作为url选项，但您正在执行以下操作：
url:ajax/getUsers.php,
Change it to:
将其更改为：
url:'ajax/getUsers.php',
What you have right now is looking for the variable ajax(which doesn't exist) then trying to divide it by the phpproperty of the object referenced by getUsers(which also doesn't exist), and then set the result as the value for the urloption.
您现在所拥有的是寻找变量ajax（不存在），然后尝试将其除以php引用的对象的属性getUsers（也不存在），然后将结果设置为url选项的值.
