bash 从文本文件中提取一行中的第二个单词
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Extract The Second Word In A Line From A Text File
提问by Aaron Perry
I am currently in need to extract the second word (CRISTOBAL) in a line in a text file.
我目前需要在文本文件的一行中提取第二个单词 (CRISTOBAL)。
* CRISTOBAL AL042014 08/05/14 12 UTC *
The second word in the line "CRISTOBAL" will vary from day to day so, I just need to find a way to extract JUST the second word/character from the line.
“CRISTOBAL”行中的第二个单词每天都会有所不同，因此，我只需要找到一种方法来仅从该行中提取第二个单词/字符。
回答by zedfoxus
2nd word
第二个字
echo '* CRISTOBAL AL042014 08/05/14 12 UTC *' | awk '{print }'
will give you CRISTOBAL
会给你 CRISTOBAL
echo 'testing only' | awk '{print }'
will give you only
会给你 only
You may have to modify this if the structure of the line changes.
如果线路的结构发生变化，您可能需要对此进行修改。
2nd word from lines in a text file
文本文件中的行中的第二个单词
If your text file contains the following two sentences
如果你的文本文件包含以下两句话
this is a test
* CRISTOBAL AL042014 08/05/14 12 UTC *
running awk '{print $2}' filename.txtwill return
跑步awk '{print $2}' filename.txt会回来
is
CRISTOBAL
2nd character
第二个字符
echo 'testing only' | cut -c 2
This will give you e, which is the 2nd character, and you may have to modify this so suit your needs also.
这会给你e，这是第二个字符，你可能需要修改它以适应你的需要。
回答by NeronLeVelu
In case of sed is needed /only available
在需要 sed 的情况下/仅可用
sed '^ *[^ ]* *\([^ ]*\) .*//' YourFile
Take second non blank group (assuming there is at least 1 blank after the word
取第二个非空白组（假设单词后面至少有 1 个空白
But I prefer cut for speed (and awk if any manip is needed).
但我更喜欢剪切速度（如果需要任何操作，则使用 awk）。
In fact it mainly depend on next action in script (if any).
事实上，它主要取决于脚本中的下一个动作（如果有的话）。
