Java Mockito.anyLong() 有什么作用？
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What does Mockito.anyLong() do?
提问by Rollerball
I have to test a method which takes a Long as argument. I have to test it for any value of the Long and also in case it's null. Does Mockito.anyLong() automatically test both cases? null and any value of the Long? Or randomly picks up a value between any long value and null? Considering that these are the docs about anyLong():
我必须测试一个以 Long 作为参数的方法。我必须测试它的任何 Long 值，以及它是否为空。Mockito.anyLong() 是否会自动测试这两种情况？null 和 Long 的任何值？或者在任意长值和空值之间随机选取一个值？考虑到这些是关于 anyLong() 的文档：
anyLong
public static long anyLong()
any long, Long or null. See examples in javadoc for Matchers class Returns: 0.
任何龙
public static long anyLong()
any long, Long or null. See examples in javadoc for Matchers class Returns: 0.
Thanks in advance.
提前致谢。
采纳答案by mpartel
It's a matcher, not a test value generator. It's used for saying things like "I expect this stubbed method to be called with any long, Long or null but I don't care about the exact value".
它是一个匹配器，而不是一个测试值生成器。它用于表示诸如“我希望使用任何 long、Long 或 null 调用此存根方法，但我不关心确切值”之类的内容。
回答by Evgeniy Dorofeev
If you have longparameter and you manage to pass nullas an argument to mock there will be NPE. If you have Longparameter anyLong()will allow Longand null, longwill be autoboxed to Longby compiler. Try this
如果您有long参数并且您设法将其null作为参数传递给模拟，则会有 NPE。如果您有Long参数anyLong()将允许Long和null，long将被Long编译器自动装箱。尝试这个
public class X {
long x(Long arg) {
return 0;
}
public static void main(String[] args) {
X x = mock(X.class);
when(x.x(anyLong())).thenReturn(0L);
System.out.println(x.x(null));
}
}
it will print
它会打印
0
0
