javascript JS 获得一个月的周数
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moment JS get number of weeks in a month
提问by h_a86
I am trying to calculate number of weeks in a month using moment js. But I am getting wrong results for some months like May 2015 and August 2015.
我正在尝试使用 moment js 计算一个月中的周数。但是我在 2015 年 5 月和 2015 年 8 月这样的几个月里得到了错误的结果。
I am using this code.
我正在使用此代码。
var start = moment().startOf('month').format('DD');
var end = moment().endOf('month').format('DD');
var weeks = (end-start+1)/7;
weeks = Math.ceil(weeks);
Is there any prebuilt method in moment JS for getting number of weeks.
在 moment JS 中是否有任何预构建的方法来获取周数。
回答by guillaumepiot
I have created this gist that finds all the weeks in a given month and year. By calculated the length of calendar, you will know the number of weeks.
我创建了这个 gist，它可以找到给定月份和年份中的所有周。通过计算 的长度calendar，您将知道周数。
https://gist.github.com/guillaumepiot/095b5e02b4ca22680a50
https://gist.github.com/guillaumepiot/095b5e02b4ca22680a50
# year and month are variables
year = 2015
month = 7 # August (0 indexed)
startDate = moment([year, month])
# Get the first and last day of the month
firstDay = moment(startDate).startOf('month')
endDay = moment(startDate).endOf('month')
# Create a range for the month we can iterate through
monthRange = moment.range(firstDay, endDay)
# Get all the weeks during the current month
weeks = []
monthRange.by('days', (moment)->
if moment.week() not in weeks
weeks.push(moment.week())
)
# Create a range for each week
calendar = []
for week in weeks
# Create a range for that week between 1st and 7th day
firstWeekDay = moment().week(week).day(1)
lastWeekDay = moment().week(week).day(7)
weekRange = moment.range(firstWeekDay, lastWeekDay)
# Add to the calendar
calendar.push(weekRange)
console.log calendar
回答by Noor
Can be easily done using raw javascript:
可以使用原始 javascript 轻松完成：
function getNumWeeksForMonth(year,month){
date = new Date(year,month-1,1);
day = date.getDay();
numDaysInMonth = new Date(year, month, 0).getDate();
return Math.ceil((numDaysInMonth + day) / 7);
}
You get the day index of the first day, add it to the number of days to compensate for the number of days lost in the first week, divide by 7 and use ceil to add 1 for the simplest overflow in the next week
你得到第一天的天数索引，把它加到天数上来补偿第一周损失的天数，除以7，然后用ceil加1为下周最简单的溢出
回答by jonruna
EDIT:
编辑：
NEW and hopefully very correct implementation:
新的，希望非常正确的实现：
function calcWeeksInMonth(date: Moment) {
const dateFirst = moment(date).date(1);
const dateLast = moment(date).date(date.daysInMonth());
const startWeek = dateFirst.isoWeek();
const endWeek = dateLast.isoWeek();
if (endWeek < startWeek) {
// Yearly overlaps, month is either DEC or JAN
if (dateFirst.month() === 0) {
// January
return endWeek + 1;
} else {
// December
if (dateLast.isoWeekday() === 7) {
// Sunday is last day of year
return endWeek - startWeek + 1;
} else {
// Sunday is NOT last day of year
return dateFirst.isoWeeksInYear() - startWeek + 1;
}
}
} else {
return endWeek - startWeek + 1;
}
}
Outputs the following values for the following dates:
输出以下日期的以下值：
calcWeeksInMonth(moment("2016-12-01")); // 5
calcWeeksInMonth(moment("2017-01-01")); // 6
calcWeeksInMonth(moment("2017-02-01")); // 5
calcWeeksInMonth(moment("2017-03-01")); // 5
calcWeeksInMonth(moment("2017-04-01")); // 5
calcWeeksInMonth(moment("2017-05-01")); // 5
calcWeeksInMonth(moment("2017-06-01")); // 5
calcWeeksInMonth(moment("2017-07-01")); // 6
calcWeeksInMonth(moment("2017-08-01")); // 5
calcWeeksInMonth(moment("2017-09-01")); // 5
calcWeeksInMonth(moment("2017-10-01")); // 6
calcWeeksInMonth(moment("2017-11-01")); // 5
calcWeeksInMonth(moment("2017-12-01")); // 5
calcWeeksInMonth(moment("2018-01-01")); // 5
OLD and very incorrect implementation:
旧且非常不正确的实现：
calcWeeksInMonth(date) {
const dateFirst = moment(date).date(1)
const dateLast = moment(date).date(date.daysInMonth())
const startWeek = dateFirst.week()
const endWeek = dateLast.week()
if (endWeek < startWeek) {
return dateFirst.weeksInYear() - startWeek + 1 + endWeek
} else {
return endWeek - startWeek + 1
}
}
This seems to output correct results, feedback welcome if there is something I missed!
这似乎输出了正确的结果，如果我错过了什么，欢迎反馈！
回答by Kanish Mathew
It display the list of weeks in a month with 'moment.js'.
It has been written in typescript with angular 6+.
它使用“moment.js”显示一个月中的周数列表。
它是用 angular 6+ 的打字稿编写的。
Install moment with 'npm i moment'
使用“npm i moment”安装 moment
Inside the ts file.
在 ts 文件中。
weeks_in_month() {
let year = 2019; // change year
let month = 4; // change month here
let startDate = moment([year, month - 1])
let endDate = moment(startDate).endOf('month');
var dates = [];
var weeks = [];
var per_week = [];
var difference = endDate.diff(startDate, 'days');
per_week.push(startDate.toDate())
let index = 0;
let last_week = false;
while (startDate.add(1, 'days').diff(endDate) < 0) {
if (startDate.day() != 0) {
per_week.push(startDate.toDate())
}
else {
if ((startDate.clone().add(7, 'days').month() == (month - 1))) {
weeks.push(per_week)
per_week = []
per_week.push(startDate.toDate())
}
else if (Math.abs(index - difference) > 0) {
if (!last_week) {
weeks.push(per_week);
per_week = [];
}
last_week = true;
per_week.push(startDate.toDate());
}
}
index += 1;
if ((last_week == true && Math.abs(index - difference) == 0) ||
(Math.abs(index - difference) == 0 && per_week.length == 1)) {
weeks.push(per_week)
}
dates.push(startDate.clone().toDate());
}
console.log(weeks);
}
Result:
结果：
Array of date moments.
日期时刻数组。
[Array(6), Array(7), Array(7), Array(7), Array(3)]
0: (6) [Mon Apr 01 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 02 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 03 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 04 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 05 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 06 2019 00:00:00 GMT+0530 (India Standard Time)]
1: (7) [Sun Apr 07 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 08 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 09 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 10 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 11 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 12 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 13 2019 00:00:00 GMT+0530 (India Standard Time)]
2: (7) [Sun Apr 14 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 15 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 16 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 17 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 18 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 19 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 20 2019 00:00:00 GMT+0530 (India Standard Time)]
3: (7) [Sun Apr 21 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 22 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 23 2019 00:00:00 GMT+0530 (India Standard Time),
Wed Apr 24 2019 00:00:00 GMT+0530 (India Standard Time),
Thu Apr 25 2019 00:00:00 GMT+0530 (India Standard Time),
Fri Apr 26 2019 00:00:00 GMT+0530 (India Standard Time),
Sat Apr 27 2019 00:00:00 GMT+0530 (India Standard Time)]
4: (3) [Sun Apr 28 2019 00:00:00 GMT+0530 (India Standard Time),
Mon Apr 29 2019 00:00:00 GMT+0530 (India Standard Time),
Tue Apr 30 2019 00:00:00 GMT+0530 (India Standard Time)]
回答by JVitela
function getWeekNums(momentObj) {
var clonedMoment = moment(momentObj), first, last;
// get week number for first day of month
first = clonedMoment.startOf('month').week();
// get week number for last day of month
last = clonedMoment.endOf('month').week();
// In case last week is in next year
if( first > last) {
last = first + last;
}
return last - first + 1;
}
回答by Erik
Here is a simple way of doing it (based on a solution posted above):
这是一个简单的方法（基于上面发布的解决方案）：
const calcWeeksInMonth = (momentDate) => {
const dateFirst = moment(momentDate).date(1)
const dateLast = moment(momentDate).date(momentDate.daysInMonth())
const startWeek = dateFirst.isoWeek()
const endWeek = dateLast.isoWeek()
if (endWeek < startWeek) {
// cater to end of year (dec/jan)
return dateFirst.weeksInYear() - startWeek + 1 + endWeek
} else {
return endWeek - startWeek + 1
}
}
As far as I can tell, it works correctly for any date thrown at it, but feedback is always welcome!
据我所知，它适用于任何抛出的日期，但始终欢迎反馈！
回答by Ian Buss
Throwing this into the mix
把这个扔进去
import moment from "moment";
export const calcWeeksInMonth = date => {
let weekMonthEnds = moment(date)
.date(moment(date).daysInMonth())
.week();
let weekMonthStarts = moment(date)
.date(1)
.week();
return weekMonthEnds < weekMonthStarts
? 52 - weekMonthStarts + 1
: weekMonthEnds - weekMonthStarts + 1;
};
回答by Mohit Bhasi
This is the best way out , works well
这是最好的出路，效果很好
moment.relativeTime.dd = function (number) {
// round to the closest number of weeks
var weeks = Math.round(number / 7);
if (number < 7) {
// if less than a week, use days
return number + " days";
} else {
// pluralize weeks
return weeks + " week" + (weeks === 1 ? "" : "s");
}
}
回答by Bigtrizzy
I have not seen a solution that works in all circumstances. I tried all of these but they all are flawed in one way or another. Ditto with several moment.js github threads. This was my crack at it:
我还没有看到适用于所有情况的解决方案。我尝试了所有这些，但它们都以一种或另一种方式存在缺陷。同上有几个 moment.js github 线程。这是我的破解：
getNumberOfWeeksInMonth = (momentDate) => {
const monthStartWeekNumber = momentDate.startOf('month').week();
const distinctWeeks = {
[monthStartWeekNumber]: true
};
let startOfMonth = momentDate.clone().startOf('month');
let endOfMonth = momentDate.clone().endOf('month');
// this is an 'inclusive' range -> iterates through all days of a month
for (let day = startOfMonth.clone(); !day.isAfter(endOfMonth); day.add(1, 'days')) {
distinctWeeks[day.week()] = true
}
return Object.keys(distinctWeeks).length;
}
回答by user3507286
function weeksInMonth(date = null){
let firstDay = moment(date).startOf('month');
let endDay = moment(date).endOf('month');
let weeks = [];
for (let i = firstDay.week(); i <= endDay.week(); i++){
weeks.push(i)
}
return weeks;
}
