javascript $.post 失败并显示错误“...不是函数”
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$.post fails with error "...is not a function"
提问by Lazloman
Here is my code:
这是我的代码：
var jqxhr = $.post("mypage.php", {url:pageurl}, function() {
alert("fetching...");
})
.success(function() { alert("fetch complete!"); })
.error(function() { alert("error!"); })
.complete(function() { alert("complete"); });
// Set another completion function for the request above
jqxhr.complete(function(){ alert("second complete"); });
I get the alert("Fetching...") dialog box, but the rest of the code does not complete. I get the error: Error: $.post("sec_fetch_report.php", function () {alert("fetching...");}).success is not a function
我收到了 alert("Fetching...") 对话框，但其余代码没有完成。我收到错误：错误：$.post("sec_fetch_report.php", function () {alert("fetching...");}).success is not a function
I thought maybe I might be missing the jquery libs, but I have another function that calls $.post and it runs just fine. Is there a syntax error I'm missing somewhere or what? Thanks
我想也许我可能缺少 jquery 库，但我有另一个调用 $.post 的函数，它运行得很好。是否有我在某处遗漏的语法错误或什么？谢谢
回答by Tejs
Your syntax is broken. What you're attempting to do is call the .success property of the $.post() method, which obviously doesnt exist. It looks like you also need to be using the $.ajaxmethod instead of $.post:
你的语法坏了。你试图做的是调用 $.post() 方法的 .success 属性，这显然不存在。看起来您还需要使用该$.ajax方法而不是$.post：
$.ajax({
type: 'POST',
url: 'mypage.php',
data: { url: pageurl },
beforeSend: function()
{
alert('Fetching....');
},
success: function()
{
alert('Fetch Complete');
},
error: function()
{
alert('Error');
},
complete: function()
{
alert('Complete')
}
});
回答by ehynds
That syntax is only supported in jQuery 1.5+ (with the introduction of deferreds). It sounds like you're using a earlier version of jQuery. If you aren't able to upgrade, pass the success/error/complete handlers as methods of the options object (like in Tejs's example).
该语法仅在 jQuery 1.5+ 中受支持（引入了延迟）。听起来您使用的是早期版本的 jQuery。如果您无法升级，请将成功/错误/完成处理程序作为选项对象的方法传递（如 Tejs 的示例）。
回答by Gary Green
The jqxhr object is chainable from v1.5. Make sure you have this version or later.
jqxhr 对象可从 v1.5 链接。确保您拥有此版本或更高版本。
回答by Scherbius.com
See examples here: jQuery.post
请参阅此处的示例：jQuery.post
also, you may get error like that if you've forgotten to link jQuery library
此外，如果您忘记链接 jQuery 库，您可能会收到类似的错误
