javascript 在javascript中返回两个字符串数组差异的函数
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Function that returns difference of two arrays of strings in javascript
提问by oneiros
Possible Duplicate:
What is the fastest or most elegant way to compute a set difference using Javascript arrays?
I need help with devising a function that will return the difference between two arrays of strings in Javascript (jQuery is acceptable as well).
我需要帮助设计一个函数，该函数将返回 Javascript 中两个字符串数组之间的差异（jQuery 也是可以接受的）。
I am basically looking for a function that calculates array A minusB.
我基本上是在寻找一个计算数组 A减去B的函数。
So if we have the followin"
所以如果我们有以下“
A = ['Istanbul', 'Hong Kong', 'Berlin']; B = ['Berlin', 'Bonn'];
Calling diff = minus(A,B)should result with diffbeing populated with the following values ['Istanbul', 'Hong Kong']
调用的diff = minus(A,B)结果应该diff是填充了以下值['Istanbul', 'Hong Kong']
I do not want to use an additional library like JS Set.
我不想使用像JS Set.
Please help with suggestions ...
请帮忙提出建议...
回答by Casey Chu
function diff(A, B) {
return A.filter(function (a) {
return B.indexOf(a) == -1;
});
}
回答by adeneo
The fastest would probably be a regular loop
最快的可能是常规循环
var A = ['Istanbul', 'Hong Kong', 'Berlin'],
B = ['Berlin', 'Bonn'],
C = [];
for (var i=A.length; i--;) {
if (B.indexOf(A[i]) === -1)
C.push(A[i]);
}
console.log(C);The most elegant is opinion-based, but something like
最优雅的是基于意见的，但像
var A = ['Istanbul', 'Hong Kong', 'Berlin'],
B = ['Berlin', 'Bonn'];
var C = A.filter(x => !B.includes(x));
console.log(C);回答by ?ime Vidas
Here:
这里：
var minus = function ( a, b ) {
return a.filter(function ( name ) {
return b.indexOf( name ) === -1;
});
};
Live demo:http://jsfiddle.net/SjF9p/
现场演示：http : //jsfiddle.net/SjF9p/
