java.text.ParseException：无法解析的日期异常
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java.text.ParseException: Unparseable date exception
提问by Magesh Balasubramaniam
If I do toStringon a Dateobject, I am getting the output as below
如果我toString在一个Date对象上做，我会得到如下输出
2016-04-13 22:00:01.0
I am doing the below to convert the object to Data again
我正在执行以下操作以再次将对象转换为数据
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd:HH:mm:SS");
Date convertedDate = (Date) formatter.parse(timestamp.toString());
But getting the ParseException.
但是得到ParseException.
I am trying to get the output as Date object as below 2016-04-13 22:00:01
我试图将输出作为日期对象，如下 2016-04-13 22:00:01
回答by Beri
This test should cover your example:
此测试应涵盖您的示例：
First from comment:
首先来自评论：
SimpleDateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss zzz yyyy");
Date convertedDate = formatter.parse("Thu Apr 14 15:24:14 CEST 2016")
System.out.print(convertedDate);
Second from question:
第二个问题：
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
Date convertedDate = formatter.parse("2016-04-13 22:00:01.0");
System.out.print(convertedDate);
It all depends on input String that you are receiving.
这一切都取决于您收到的输入字符串。
You should not use Date::toString method, use formatter, as you willl have no problem with zones and formats. It's better to have full flow control over your data.
你不应该使用 Date::toString 方法，使用格式化程序，因为你不会有区域和格式的问题。最好对您的数据进行完全的流量控制。
Now if you want to convert it to a " 2016-04-13 22:00:01" format, simply use:
现在，如果您想将其转换为“2016-04-13 22:00:01”格式，只需使用：
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String formatedDate = formatter.format(convertedDate);
回答by subrunner
Parse from String with a certain date-format to a Date object:
从具有特定日期格式的 String 解析为 Date 对象：
String dateString = "2016-04-13 22:00:01.0";
SimpleDateFormat formatterFullMilliseconds = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss.SSS" );
Date dateFromDateString = formatterFullMilliseconds.parse( dateString );
System.out.println( dateFromDateString ); // Output: Wed Apr 13 22:00:01 CEST 2016
Parse a java.util.Date object to the string representation you want:
将 java.util.Date 对象解析为您想要的字符串表示形式：
SimpleDateFormat formatter = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss" );
System.out.println( formatter.format( dateFromDateString ) ); // 2016-04-13 22:00:01
System.out.println( formatter.format( new Date() ) ); // 2016-04-14 15:29:04
回答by Firdous Ahmad
This is exactly what you need to do, to escape java.text.ParseException: Unparseable date exception
这正是您需要做的，以逃避 java.text.ParseException: Unparseable date exception
Date date = new Date();
SimpleDateFormat sp = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date dt = sp.parse(sp.format(date));
System.out.println(dt.toString());
回答by John K
yyyy-MM-dd:HH:mm:SS
should be
应该
yyyy-MM-dd HH:mm:ss.S
