java 从电话号码中删除括号、破折号和空格

Remove parentheses, dashes, and spaces from phone number

提问by user3786942

I have a phone number like [phone]. I am using the replaceAllmethod to remove ()and -and spaces from the string. I tried following

我有一个电话号码，如 [phone]。我正在使用该replaceAll方法从字符串中删除()和-和空格。我试过跟随

String phNo= "[phone]".replaceAll("[()-\s]").trim();

but it's not working. Any solution?

但它不起作用。有什么解决办法吗？

回答by anubhava

This should work:

这应该有效：

String phNo = "[phone]".replaceAll("[()\s-]+", "");

In your regex:

在您的正则表达式中：

• \sshould be \\s
• Hyphen should be first or last in character class to avoid escaping or use it as \\-
• Use quantifier +as in [()\\s-]+to increase efficiency by minimizing # of replacements

• \s应该 \\s
• 连字符应该在字符类中的第一个或最后一个以避免转义或将其用作 \\-
• 使用量词+as in[()\\s-]+通过最小化替换次数来提高效率

回答by Andie2302

If you want the phone number then use:

如果您想要电话号码，请使用：

String phNo = "[phone]".replaceAll("\D+", "");

This regex will mark all characters that are not digits, and replace them with an empty string.

此正则表达式将标记所有不是数字的字符，并用空字符串替换它们。

---

---

The regex: \D+

正则表达式： \D+

• Match a single character that is not a digit. \D
  • Between one and unlimited times, as many times as possible. +

• 匹配非数字的单个字符。 \D
  • 在一次和无限次之间，尽可能多次。 +

回答by katwal-Dipak

  String newStr = phoneNumber.replaceAll("[^0-9]", "");
        System.out.println(newStr);

Removes All Non-Digit Characters.

删除所有非数字字符。

Java Regex - Tutorial

Java 正则表达式 - 教程

回答by rgettman

The -character with brackets []indicates a character range, e.g. [a-z]. However, the character range doesn't work here where you want a literal -to be used. Escape it.

在-用括号字符[]指示字符范围内，例如[a-z]。但是，字符范围在您想要使用文字的地方不起作用-。逃离它。

String phNo = "[phone]".replaceAll("[()\-\s]", "").trim());

回答by hwnd

There are two main reasons this does not work as expected.

这没有按预期工作有两个主要原因。

1. Inside of a character class the hyphen has special meaning. You can place a hyphen as the first or last character of the class. In some regular expression implementations, you can also place directly after a range. If you place the hyphen anywhere else you need to escape it in order to add it to your class.

   String phNo = "[phone]".replaceAll("[()\-\s]").trim();
                                                 ^^
   

2. You are not supplying a replacement value which neither answer has pointed out to you.

   String phNo = "[phone]".replaceAll("[()\-\s]", "").trim();
                                                           ^^
   

   And finally, you can remove .trim()here as well.

   String phNo = "[phone]".replaceAll("[()\-\s]", "");
   

1. 在字符类中，连字符具有特殊含义。您可以将连字符作为类的第一个或最后一个字符。在一些正则表达式的实现中，你也可以直接放在一个范围之后。如果您将连字符放在其他任何地方，则需要将其转义以将其添加到您的类中。

   String phNo = "[phone]".replaceAll("[()\-\s]").trim();
                                                 ^^
   

2. 您没有提供两个答案都没有向您指出的替代价值。

   String phNo = "[phone]".replaceAll("[()\-\s]", "").trim();
                                                           ^^
   

   最后，您也可以.trim()在此处删除。

   String phNo = "[phone]".replaceAll("[()\-\s]", "");
   

回答by Mohit Suthar

If you are using Kotlin than

如果您使用的是 Kotlin，那么

mobileNo.replace(Regex("[()\\-\\s]"), "")

mobileNo.replace(Regex("[()\\-\\s]"), "")