C++ 初始化二维字符串数组
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Initializing a two dimensional array of strings
提问by honey
How to declare a two dimensional array of strings in c++? And also how to write this string on files?
如何在 C++ 中声明一个二维字符串数组？还有如何在文件上写这个字符串？
回答by honey
Declaration and initialization together:
一起声明和初始化：
std::string myarray[2][3] = {
{ "hello", "Hyman", "dawson" },
{ "hello", "hello", "hello" }
};
For writing to file, templatetypedef's answer is almost fine, except you should do error checking and close the output file stream when done.
对于写入文件，templatetypedef 的答案几乎没问题，除非您应该进行错误检查并在完成后关闭输出文件流。
回答by Mark Ransom
typedef std::vector<std::string> StringVector;
typedef std::vector<StringVector> StringVector2D;
StringVector2D twoD;
for (StringVector2D::iterator outer = twoD.begin(); outer != twoD.end(); ++outer)
for (StringVector::iterator inner = outer->begin(); inner != outer->end(); ++inner)
std::cout << *inner << std::endl;
回答by templatetypedef
You can declare a multidimensional array of strings like this:
您可以像这样声明一个多维字符串数组：
std::string myArray[137][42];
Of course, substituting your own width/height values for 137 and 42. :-)
当然，将您自己的宽度/高度值替换为 137 和 42。:-)
There's no "one right way" to write this array to disk. You'll essentially be iterating over the array writing one string at a time to disk, with some sort of appropriate separators and error-checking logic. Here's one naive implementation, which writes out one string per line (assuming that the strings don't have any newlines in them):
没有“一种正确的方法”可以将此数组写入磁盘。您基本上将迭代数组，一次将一个字符串写入磁盘，并使用某种适当的分隔符和错误检查逻辑。这是一个简单的实现，它每行写出一个字符串（假设字符串中没有任何换行符）：
std::ofstream output("result.txt");
for (size_t i = 0; i < 137; ++i)
for (size_t j = 0; j < 42; ++j)
output << myArray[i][j] << std::endl;
Hope this helps!
希望这可以帮助！
回答by Manish Bhadani
#include<iostream>
#include<vector>
using namespace std;
main()
{
vector< vector<string> > m2m;
vector<string> A, B;
vector< vector<string> >::iterator inter_i;
vector<string>::iterator inter_j;
A.push_back("micro");
A.push_back("soft");
A.push_back("bilgates");
B.push_back("linux");
B.push_back("unix");
B.push_back("ken dennish");
m2m.push_back(A);
m2m.push_back(B);
cout<<endl<<" USing iterator : "<<endl;
for(inter_i=m2m.begin();inter_i!=m2m.end();inter_i++)
{
for(inter_j=(*inter_i).begin();inter_j!=(*inter_i).end();inter_j++)
{
cout<<*inter_j<<" ";
}
cout<<endl;
}
return 0;
}
回答by Arenim
I assume, that You've QString type. This should work to std::string and even (char*) properly.
我假设，你有 QString 类型。这应该适用于 std::string 甚至 (char*) 正确。
QString ** myTwoDimensionalArray;
myTwoDimensionalArray = new QString*[size_x];
for(int i=0; i<size_x; i++) myTwoDimensionalArray[i] = new QString[size_y];
That's it. Now, You can write something like:
就是这样。现在，您可以编写如下内容：
myTwoDimensionalArray[x][y] = "Hello, World!";
