java 我如何遍历一个 int
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How do I iterate through an int
提问by user2803555
I get an "int cannot be dereferenced" It might be because .lenght on it, What else can I do to iterate through the int?
我得到一个“int 不能被取消引用”这可能是因为 .lenght 在它上面，我还能做些什么来遍历 int？
int num;
System.out.print("Enter a positive integer: ");
num = console.nextInt();
if (num > 0)
for (int i = 0; i < num.lenght; i++)
System.out.println();
回答by T3 H40
for (int i = 0; i < num; i++)
for (int i = 0; i < num; i++)
Your numalready is a number. So your condition will suffice like above.
你num已经是一个数字。所以你的条件就足够了。
Example:If the user enters 4, the for statement will evaluate to
for (int i = 0; i < 4; i++), running the loop four times, with ihaving the values 0, 1, 2and 3
示例：如果用户输入4，for 语句将评估为
for (int i = 0; i < 4; i++)，运行循环四次，i具有值0, 1, 2和3
If you wanted to iterate over each digit, you would need to turn your int back to a stringfirst, and then loop over each characterin this string:
如果你想遍历每个数字，你需要先把你的int 转回一个字符串，然后循环这个字符串中的每个字符：
String numberString = Integer.toString(num);
for (int i = 0; i < numberString.length(); i++){
char c = numberString.charAt(i);
//Process char
}
If you wanted to iterate the binary representationof your number, have a look at thisquestion, it might help you.
如果你想迭代你的数字的二进制表示，看看这个问题，它可能对你有帮助。
Note:though it might not be required, I would suggest you to use {}-brackets around your statement blocks, to improve readability and reduce chance of mistakes like this:
注意：虽然可能不是必需的，但我建议您{}在语句块周围使用-brackets，以提高可读性并减少出现以下错误的机会：
if (num > 0) {
for (int i = 0; i < num; i++) {
System.out.println();
}
}
回答by user2173372
Try the following code:
试试下面的代码：
import java.util.Scanner;
public class IntExample {
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.print("Enter a positive integer: ");
int num = console.nextInt();
console.close();
if (num > 0) {
for (int i = 0; i < num; i++) {
System.out.println(i);
}
}
}
}
