Java 如何将包含负数的字符串解析为整数？
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How to parse string containing negative number into integer?
提问by Suroor Ahmmad
Part of my code is here!
我的部分代码在这里！
bufferedReader=new BufferedReader (inputstreamreader);
message=bufferedReader.readLine ();// ex: message has (1,-3)
String[] msg=message.split (",") //I use comma (,) as deliminator
int x=Integer.parseInt (msg [0]);
int y=Integer.parseInt (msg [1]);
This clearly parses but the problem is it looses negative sign. That is the "message" contains (1,-3). Pls help me to parse without loosing -ve sign.
这显然可以解析，但问题是它丢失了负号。即“消息”包含 (1,-3)。请帮助我在不丢失 -ve 符号的情况下进行解析。
采纳答案by Smutje
String message = "1,-3";
String[] msg = message.split(",");
int x = Integer.parseInt(msg[0]);
int y = Integer.parseInt(msg[1]);
System.out.println(x);
System.out.println(y);
Works without a problem. Output:
工作没有问题。输出：
1
-3
1
-3
回答by Karthik Prasad
ParseIntShould work, however you are not getting the result because String[] msg = message.split(",");results in 2 strings with "(1" and other "-10)" try to remove the braces
ParseInt应该可以工作，但是您没有得到结果，因为String[] msg = message.split(",");结果是 2 个带有“(1”和其他“-10)”的字符串尝试删除大括号
