Java 从日期字符串中提取时间
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Extract time from date String
提问by JJunior
How can I format the "2010-07-14 09:00:02"date string to depict just "9:00"?
如何格式化"2010-07-14 09:00:02"日期字符串以仅描述"9:00"？
采纳答案by BalusC
Use SimpleDateFormatto convert between a date string and a real Dateobject. with a Dateas starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the SimpleDateFormat(click the blue code link for the Javadoc).
用于SimpleDateFormat在日期字符串和真实Date对象之间进行转换。以Date为起点，您可以轻松地应用基于 Javadoc 中定义的各种模式的格式SimpleDateFormat（单击 Javadoc 的蓝色代码链接）。
Here's a kickoff example:
这是一个启动示例：
String originalString = "2010-07-14 09:00:02";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(originalString);
String newString = new SimpleDateFormat("H:mm").format(date); // 9:00
回答by MikeTheReader
I'm assuming your first string is an actual Date object, please correct me if I'm wrong. If so, use the SimpleDateFormat object: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html. The format string "h:mm" should take care of it.
我假设你的第一个字符串是一个实际的 Date 对象，如果我错了，请纠正我。如果是这样，请使用 SimpleDateFormat 对象：http: //download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html。格式字符串 "h:mm" 应该处理它。
回答by Adam
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2010-07-14 09:00:02");
String time = new SimpleDateFormat("H:mm").format(date);
http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html
http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html
回答by Petr Pudlák
A very simple way is to use Formatter(see date time conversions) or more directly String.formatas in
一个非常简单的方法是使用Formatter（参见日期时间转换）或更直接地，String.format如
String.format("%tR", new Date())
回答by Bohdan Kolesnyk
If you have date in integers, you could use like here:
如果你有整数日期，你可以在这里使用：
Date date = new Date();
date.setYear(2010);
date.setMonth(07);
date.setDate(14)
date.setHours(9);
date.setMinutes(0);
date.setSeconds(0);
String time = new SimpleDateFormat("HH:mm:ss").format(date);
回答by BHAVIK PANCHAL
let datestring = "2017-02-14 02:16:28"
let formatter = DateFormatter()
formatter.dateStyle = DateFormatter.Style.full
formatter.timeStyle = DateFormatter.Style.full
formatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
let date = formatter.date(from: datestring)
let date2 = formatter.String(from: date)
回答by Ole V.V.
The other answers were good answers when the question was asked. Time moves on, Dateand SimpleDateFormatget replaced by newer and better classes and go out of use. In 2017, use the classes in the java.timepackage:
当问题被问到时，其他答案都是很好的答案。在每次移动，Date并SimpleDateFormat获得通过更新更好的替代课程，去使用了。2017年使用java.time包中的类：
String timeString = LocalDateTime.parse(dateString, DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"))
.format(DateTimeFormatter.ofPattern("H:mm"));
The result is the desired, 9:00.
结果是想要的，9:00。
