Ruby 在与源相同的目录中加载配置 (yaml) 文件
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Ruby loading config (yaml) file in same dir as source
提问by FelixHJ
in HOME/path_test/ I have:
在 HOME/path_test/ 我有：
load_test.rb:
load_test.rb:
require 'yaml'
cnf = YAML::load(File.open('config.yml'))
puts cnf['Hello']
config.yml:
配置文件：
Hello: world!!!
when in HOME/path_test/ I get as expected:
当在 HOME/path_test/ 我得到预期：
-bash-3.2$ ruby load_test.rb
world!!!
when in HOME/ (cd ..) I get
当在 HOME/ (cd ..) 我得到
-bash-3.2$ ruby path_test/load_test.rb
path_test/load_test.rb:3:in `initialize': No such file or directory - config.yml (Errno::ENOENT)
from path_test/load_test.rb:3:in `open'
from path_test/load_test.rb:3:in `<main>'
Which is correct behavior, but not what I had wished for :)
这是正确的行为，但不是我所希望的:)
Is there a way to load the .yml file relative to the source file, and not relative to the current working DIR??
有没有办法相对于源文件而不是相对于当前工作目录加载 .yml 文件？
Solution (load_Test.rb):
解决方案（load_Test.rb）：
require 'yaml'
fn = File.dirname(File.expand_path(__FILE__)) + '/config.yml'
cnf = YAML::load(File.open(fn))
puts cnf['Hello']
回答by Hauleth
You should get path of the current file by:
您应该通过以下方式获取当前文件的路径：
cnf = YAML::load_file(File.join(File.dirname(File.expand_path(__FILE__)), 'config.yml'))
EDIT:
编辑：
Since Ruby 2.0 you can simplify that and use:
从 Ruby 2.0 开始，您可以简化并使用：
cnf = YAML::load_file(File.join(__dir__, 'config.yml'))
