Java 如何将 JSON 对象流式传输到 HttpURLConnection POST 请求

How to stream a JSON object to a HttpURLConnection POST request

提问by AgilePro

I can not see what is wrong with this code:

我看不出这段代码有什么问题：

JSONObject msg;  //passed in as a parameter to this method

HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setDoOutput(true);
httpCon.setDoInput(true);
httpCon.setUseCaches(false);
httpCon.setRequestProperty( "Content-Type", "application/json" );
httpCon.setRequestProperty("Accept", "application/json");
httpCon.setRequestMethod("POST");
OutputStream os = httpCon.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os, "UTF-8");
msg.write(osw);
osw.flush();
osw.close();    
os.close();     //probably overkill

On the server, I am getting no post content at all, a zero length string.

在服务器上，我根本没有收到任何帖子内容，一个零长度的字符串。

采纳答案by Yser

Try

尝试

...
httpCon.setRequestMethod("POST");
httpCon.connect(); // Note the connect() here
...
OutputStream os = httpCon.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os, "UTF-8");
...    
osw.write(msg.toString());
osw.flush();
osw.close();

to send data.

发送数据。

to retrieve data try:

检索数据尝试：

BufferedReader br = new BufferedReader(new InputStreamReader( httpCon.getInputStream(),"utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
    sb.append(line + "\n");
}
br.close();
System.out.println(""+sb.toString());

回答by hgoebl

HttpURLConnectionis cumbersome to use. With DavidWebb, a tiny wrapper around HttpURLConnection, you can write it like this:

HttpURLConnection使用起来很麻烦。使用DavidWebb，一个围绕 HttpURLConnection 的小包装，你可以这样写：

JSONObject msg;  //passed in as a parameter to this method

Webb webb = Webb.create();
JSONObject result = webb.post("http://my-url/path/to/res")
    .useCaches(false)
    .body(msg)
    .ensureSuccess()
    .asJsonObject()
    .getBody();

If you don't like it, there is a list of alternative libraries on the link provided.

如果您不喜欢它，提供的链接上有一个替代库列表。

Why should we all write the same boilerplate code every day? BTW the code above is more readable and less error-prone. HttpURLConnectionhas an awful interface. This has to be wrapped!

为什么我们每天都要编写相同的样板代码？顺便说一句，上面的代码更具可读性且不易出错。HttpURLConnection有一个糟糕的界面。这个必须包！

回答by Pablo Rodriguez Bertorello

Follow this example:

按照这个例子：

public static PricesResponse getResponse(EventRequestRaw request) {

    // String urlParameters  = "param1=a&param2=b&param3=c";
    String urlParameters = Piping.serialize(request);

    HttpURLConnection conn = RestClient.getPOSTConnection(endPoint, urlParameters);

    PricesResponse response = null;

    try {
        // POST
        OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
        writer.write(urlParameters);
        writer.flush();

        // RESPONSE
        BufferedReader reader = new BufferedReader(new InputStreamReader((conn.getInputStream()), StandardCharsets.UTF_8));
        String json = Buffering.getString(reader);
        response = (PricesResponse) Piping.deserialize(json, PricesResponse.class);

        writer.close();
        reader.close();

    } catch (Exception e) {
        e.printStackTrace();
    }

    conn.disconnect();

    System.out.println("PricesClient: " + response.toString());

    return response;
}


public static HttpURLConnection getPOSTConnection(String endPoint, String urlParameters) {

    return RestClient.getConnection(endPoint, "POST", urlParameters);

}


public static HttpURLConnection getConnection(String endPoint, String method, String urlParameters) {

    System.out.println("ENDPOINT " + endPoint + " METHOD " + method);
    HttpURLConnection conn = null;

    try {
        URL url = new URL(endPoint);
        conn = (HttpURLConnection) url.openConnection();
        conn.setRequestMethod(method);
        conn.setDoOutput(true);
        conn.setRequestProperty("Content-Type", "text/plain");

    } catch (IOException e) {
        e.printStackTrace();
    }

    return conn;
}

回答by Mahadev Dalavi

 public String sendHTTPData(String urlpath, JSONObject json) {
        HttpURLConnection connection = null;
        try {
            URL url=new URL(urlpath);
            connection = (HttpURLConnection) url.openConnection();
            connection.setDoOutput(true);
            connection.setDoInput(true);
            connection.setRequestMethod("POST");
            connection.setRequestProperty("Content-Type", "application/json");
            connection.setRequestProperty("Accept", "application/json");
            OutputStreamWriter streamWriter = new OutputStreamWriter(connection.getOutputStream());
            streamWriter.write(json.toString());
            streamWriter.flush();
            StringBuilder stringBuilder = new StringBuilder();
            if (connection.getResponseCode() == HttpURLConnection.HTTP_OK){
                InputStreamReader streamReader = new InputStreamReader(connection.getInputStream());
                BufferedReader bufferedReader = new BufferedReader(streamReader);
                String response = null;
                while ((response = bufferedReader.readLine()) != null) {
                    stringBuilder.append(response + "\n");
                }
                bufferedReader.close();

                Log.d("test", stringBuilder.toString());
                return stringBuilder.toString();
            } else {
                Log.e("test", connection.getResponseMessage());
                return null;
            }
        } catch (Exception exception){
            Log.e("test", exception.toString());
            return null;
        } finally {
            if (connection != null){
                connection.disconnect();
            }
        }
    }`

call this methopd in doitbackground in asynctask

在 asynctask 的 doitbackground 中调用此方法

回答by Mahadev Dalavi

this without json String post data to server

这没有 json 字符串将数据发布到服务器

 class PostLogin extends AsyncTask<Void, Void, String> {
        @Override
        protected String doInBackground(Void... params) {
            String response = null;

            Uri.Builder builder= new Uri.Builder().appendQueryParameter("username","amit").appendQueryParameter("password", "amit");
            String parm=builder.build().getEncodedQuery();
      try
           {

               response = postData("your url here/",parm);
           }catch (Exception e)
           {
               e.printStackTrace();
           }
            Log.d("test", "response string is:" + response);
            return response;
        }
    }


private String postData(String path, String param)throws IOException {
        StringBuffer response = null;

        URL  url = new URL(path);
        HttpURLConnection  connection = (HttpURLConnection) url.openConnection();
        connection.setRequestMethod("POST");
        connection.setDoOutput(true);
//        connection.setRequestProperty("Content-Type", "application/json");
//        connection.setRequestProperty("Accept", "application/json");
            OutputStream out = connection.getOutputStream();
            out.write(param.getBytes());
            out.flush();
            out.close();
            int responseCode = connection.getResponseCode();
            if (responseCode == HttpURLConnection.HTTP_OK) {
                BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
                String line;
                response = new StringBuffer();
                while ((line = br.readLine()) != null) {
                    response.append(line);
                }
                br.close();
            }

        return response.toString();
    }