Python 具有随机像素颜色的 100x100 图像
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100x100 image with random pixel colour
提问by IceDragon
I'm trying to make a 100x100image with each pixel being a different random colour, like this example:
我正在尝试制作100x100每个像素为不同随机颜色的图像，如下例所示：
I've tried to use matplotlibbut I'm not having much luck. Should I maybe be using PIL?
我试过使用，matplotlib但运气不佳。我应该使用 PIL 吗？
采纳答案by Hooked
This is simple with numpyand pylab. You can set the colormap to be whatever you like, here I use spectral.
这很简单，用numpy和pylab。您可以将颜色图设置为您喜欢的任何内容，这里我使用光谱。
from pylab import imshow, show, get_cmap
from numpy import random
Z = random.random((50,50)) # Test data
imshow(Z, cmap=get_cmap("Spectral"), interpolation='nearest')
show()
Your target image looks to have a grayscale colormap with a higher pixel density than 100x100:
您的目标图像看起来具有像素密度高于 100x100 的灰度颜色图：
import pylab as plt
import numpy as np
Z = np.random.random((500,500)) # Test data
plt.imshow(Z, cmap='gray', interpolation='nearest')
plt.show()
回答by heltonbiker
If you want to create an image file (and display it elsewhere, with or without Matplotlib), you could use Numpy and PIL as follows:
如果你想创建一个图像文件（并在其他地方显示它，有或没有 Matplotlib），你可以使用 Numpy 和 PIL，如下所示：
import numpy, Image
imarray = numpy.random.rand(100,100,3) * 255
im = Image.fromarray(imarray.astype('uint8')).convert('RGBA')
im.save('result_image.png')
The idea here is to create a numeric array, convert it to a RGB image, and save it to file. If you want grayscale image, you should use convert('L')instead of convert('RGBA').
这里的想法是创建一个数字数组，将其转换为 RGB 图像，并将其保存到文件中。如果你想要灰度图像，你应该使用convert('L')而不是convert('RGBA').
Hope this helps
希望这可以帮助
回答by PaulMcG
I wanted to write some simple BMP files, so I researched the format and wrote a very simple bmp.py module:
我想写一些简单的 BMP 文件，所以我研究了格式并写了一个非常简单的bmp.py 模块：
# get bmp.py at http://www.ptmcg.com/geo/python/bmp.py.txt
from bmp import BitMap, Color
from itertools import product
from random import randint, choice
# make a list of 256 colors (all you can fit into an 8-bit BMP)
colors = [Color(randint(0,255), randint(0,255), randint(0,255))
for i in xrange(256)]
bmp = BitMap(100,100)
for x,y in product(xrange(100),xrange(100)):
bmp.setPenColor(choice(colors))
bmp.plotPoint(x,y)
bmp.saveFile("100x100.bmp", compress=False)
Sample 100x100.bmp:
示例 100x100.bmp：
For a slightly larger pixel size, use:
对于稍大的像素尺寸，请使用：
PIXEL_SIZE=5
bmp = BitMap(PIXEL_SIZE*100,PIXEL_SIZE*100)
for x,y in product(xrange(100),xrange(100)):
bmp.setPenColor(choice(colors))
bmp.drawSquare(x*PIXEL_SIZE,y*PIXEL_SIZE,PIXEL_SIZE,fill=True)
filename = "%d00x%d00.bmp" % (PIXEL_SIZE,PIXEL_SIZE)
bmp.saveFile(filename)
You may not want to use bmp.py, but this shows you the general idea of what you'll need to do.
您可能不想使用 bmp.py，但这向您展示了您需要做什么的总体思路。
回答by user2145646
I believe the colour map of that array to be bone, i.e.
我相信该数组的颜色图是骨骼，即
#import the modules
import numpy as np
import matplotlib.cm as cm
import matplotlib.pyplot as plt
rand_array=np.random.rand(550,550) #create your array
plt.imshow(rand_array,cmap=cm.bone) #show your array with the selected colour
plt.show() #show the image
Should produce what you're looking for :)
应该产生你正在寻找的东西:)
EDIT: Just change 550 to 100 if you want a 100x100 array
编辑：如果你想要一个 100x100 的数组，只需将 550 更改为 100
回答by banderlog013
import numpy as np
import matplotlib.pyplot as plt
img = (np.random.standard_normal([28, 28, 3]) * 255).astype(np.uint8)
plt.imshow(img)
Will give you this 28x28 RGB image:
会给你这个 28x28 RGB 图像：
