jQuery getJSON 到外部 PHP 页面
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jQuery getJSON to external PHP page
提问by Pmarcoen
I've been trying to make an AJAX request to an external server. I've learned so far that I need to use getJSON to do this because of security reasons ?
我一直在尝试向外部服务器发出 AJAX 请求。到目前为止，我已经了解到出于安全原因我需要使用 getJSON 来执行此操作？
Now, I can't seem to make a simple call to an external page. I've tried to simplify it down as much as I can but it's still not working. I have 2 files, test.html & test.php
现在，我似乎无法对外部页面进行简单调用。我试图尽可能地简化它，但它仍然不起作用。我有 2 个文件，test.html 和 test.php
my test.html makes a call like this, to localhost for testing :
我的 test.html 像这样调用本地主机进行测试：
$.getJSON("http://localhost/OutVoice/services/test.php", function(json){
alert("JSON Data: " + json);
});
and I want my test.php to return a simple 'test' :
我希望我的 test.php 返回一个简单的“测试”：
$results = "test";
echo json_encode($results);
I'm probably making some incredible rookie mistake but I can't seem to figure it out. Also, if this works, how can I send data to my test.php page, like you would do like test.php?id=15 ?
我可能犯了一些令人难以置信的菜鸟错误，但我似乎无法弄清楚。另外，如果这有效，我如何将数据发送到我的 test.php 页面，就像你会像 test.php?id=15 那样？
The test.html page is calling the test.php page on localhost, same directory I don't get any errors, just no alert ..
test.html 页面正在调用本地主机上的 test.php 页面，同一目录我没有收到任何错误，只是没有警报..
回答by moff
It couldbe that you haven't got a callback in test.php. Also, json_encodeonly accepts an array:
这可能是你没有在test.php的回调。此外，json_encode只接受一个数组：
$results = array("key" => "value");
echo $_GET['callback'] . '(' . json_encode($results) . ')';
// the callback stuff is only needed if you're requesting from different domains
jQuery automatically switches to JSONP (i.e. using script tags instead of XMLHttpRequest) when you use http://. If you have test.html and test.php on the same domain, try using relative paths (and no callbacks).
jQuery将自动切换到JSONP（即使用脚本标记代替XMLHttpRequest）当您使用http://。如果您在同一个域中有 test.html 和 test.php，请尝试使用相对路径（并且没有回调）。
回答by drewish
Be careful with moff's answer. It's got a common XSS vulnerability: http://www.metaltoad.com/blog/using-jsonp-safely
小心 moff 的回答。它有一个常见的 XSS 漏洞：http: //www.metaltoad.com/blog/using-jsonp-safely
回答by Ally
The simplest solution would be to add the below code before any output to your test.php file, then you have more flexibility with what methods you use, a standard ajax call should work.
最简单的解决方案是在 test.php 文件的任何输出之前添加以下代码，然后您可以更灵活地使用哪些方法，标准的 ajax 调用应该可以工作。
header ('Access-Control-Allow-Origin: *');
However, use the json callback thing when your getting data from a server beyond your control.
但是，当您从无法控制的服务器获取数据时，请使用 json 回调。
