在 Bash 中，如何安全地确定软链接指向的内容？
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In Bash, how do I safely determine what a soft link points to?
提问by swestrup
I need to process a number of directories, determine what files in them are symlinks, and what they link to. This sounds simple, but I have no control over the presence of control or other characters in the file names, and I need a robust solution.
我需要处理多个目录，确定其中的哪些文件是符号链接，以及它们链接到的内容。这听起来很简单，但我无法控制文件名中是否存在控件或其他字符，我需要一个强大的解决方案。
So, given a file of arbitrary name, how do I safely determine what it links to, when the link destination can also have arbitrary contents?
那么，给定一个任意名称的文件，当链接目的地也可以包含任意内容时，我如何安全地确定它链接到的内容？
回答by eduffy
回答by Konstantinos Roditakis
stat <linkname>
Example:
例子：
stat /usr/local/cuda
First 2 lines will give:
前两行将给出：
File: '/usr/local/cuda' -> 'cuda-8.0'
Size: 8 Blocks: 0 IO Block: 4096 symbolic link
...
回答by Sero
Python 2 script that traces/follows symbolic links provided as arguments.
跟踪/跟踪作为参数提供的符号链接的 Python 2 脚本。
listSymLink.py
listSymLink.py
import os.path as OSPath
import os
import sys
for arg in sys.argv[1:]:
if OSPath.exists(arg):
pathTrail = [OSPath.abspath(arg)]
while OSPath.islink(pathTrail[-1]):
linkTarget = os.readlink(pathTrail[-1])
if not OSPath.isabs(linkTarget):
linkTarget = OSPath.join(os.path.dirname(pathTrail[-1]), linkTarget)
pathTrail.append(linkTarget)
print " -> ".join(map(lambda x: "\"" + x + "\"", pathTrail))
else:
print "\"" + arg + "\" path doesn't exist"
Example
例子
python listSymLink.py /usr/bin/c++
prints
印刷
"/usr/bin/c++" -> "/etc/alternatives/c++" -> "/usr/bin/g++" -> "/usr/bin/g++-8" -> "/usr/bin/x86_64-linux-gnu-g++-8"
