php php检查数组是否包含来自另一个数组的所有数组值
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php check if array contains all array values from another array
提问by peter
$all = array
(
0 => 307,
1 => 157,
2 => 234,
3 => 200,
4 => 322,
5 => 324
);
$search_this = array
(
0 => 200,
1 => 234
);
I would like to find out if $all contains all $search_this values and return true or false. any idea please?
我想知道 $all 是否包含所有 $search_this 值并返回 true 或 false。有什么想法吗？
回答by orrd
The previous answers are all doing more work than they need to. Just use array_diff. This is the simplest way to do it:
以前的答案都做了比他们需要的更多的工作。只需使用array_diff。这是最简单的方法：
$containsAllValues = !array_diff($search_this, $all);
That's all you have to do.
这就是你所要做的。
回答by jasonbar
Look at array_intersect().
$containsSearch = count(array_intersect($search_this, $all)) == count($search_this);
回答by javigzz
A bit shorter with array_diff
使用array_diff短一点
$musthave = array('a','b');
$test1 = array('a','b','c');
$test2 = array('a','c');
$containsAllNeeded = 0 == count(array_diff($musthave, $test1));
// this is TRUE
$containsAllNeeded = 0 == count(array_diff($musthave, $test2));
// this is FALSE
回答by James Kyburz
I think you're looking for the intersect function
我想你正在寻找 intersect 函数
array array_intersect ( array $array1 , array $array2 [, array $ ... ] )
array_intersect()returns an array containing all values of array1 that are
present in all the arguments. Note that keys are preserved.
array_intersect()返回一个数组，其中包含所有参数中出现的 array1 的所有值。请注意，密钥被保留。
回答by K-Alex
How about this:
这个怎么样：
function array_keys_exist($searchForKeys = array(), $searchableArray) {
$searchableArrayKeys = array_keys($searchableArray);
return count(array_intersect($searchForKeys, $searchableArrayKeys)) == count($searchForKeys); }
function array_keys_exist($searchForKeys = array(), $searchableArray) {
$searchableArrayKeys = array_keys($searchableArray);
return count(array_intersect($searchForKeys, $searchableArrayKeys)) == count($searchForKeys); }
