Java 如何为 JSP 配置 spring boot mvc 应用程序？
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How to configure spring boot mvc app for JSP?
提问by Rakesh Juyal
I am new to Spring boot ( and servlet 3.0 ). I am trying to create spring mvc project with JSP as view. When I return a view from my controller it is not getting resolved as JstlView.
我是 Spring Boot（和 servlet 3.0）的新手。我正在尝试使用 JSP 作为视图创建 spring mvc 项目。当我从控制器返回一个视图时，它没有被解析为 JstlView。
Here is what I did:
这是我所做的：
@SpringBootApplication
public class MyApp extends SpringBootServletInitializer {
public static void main(String[] args) {
SpringApplication.run(MyApp.class, args);
}
}
@Controller
public class MainController {
@RequestMapping( value="/main" , method = RequestMethod.GET )
public String main(){
return "main";
}
@RequestMapping( value="/" , method = RequestMethod.GET )
public String welcome(){
return "welcome";
}
}
Created both .jsp files in src\main\webapp\WEB-INF\jsp.
在 .jsp 文件中创建了两个 .jsp 文件src\main\webapp\WEB-INF\jsp。
After googling I found that I need to specify this in application.properties So I added following in props:
谷歌搜索后，我发现我需要在 application.properties 中指定它，所以我在 props 中添加了以下内容：
spring.mvc.view.prefix: /WEB-INF/jsp/
spring.mvc.view.suffix: .jsp
logging.level.org.springframework: TRACE
logging.level.com: TRACE
Even after this it is not working. Here is the trace.
即使在此之后它也不起作用。这是踪迹。
2016-04-24 19:54:49.016 TRACE 7880 --- [nio-8080-exec-1] .w.s.m.m.a.ServletInvocableHandlerMethod : Invoking [MainController.welcome] method with arguments []
2016-04-24 19:54:49.016 TRACE 7880 --- [nio-8080-exec-1] .w.s.m.m.a.ServletInvocableHandlerMethod : Method [welcome] returned [welcome]
2016-04-24 19:54:49.020 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.s.v.ContentNegotiatingViewResolver : Requested media types are [text/html, application/xhtml+xml, image/webp, application/xml;q=0.9, */*;q=0.8] based on Accept header types and producible media types [*/*])
2016-04-24 19:54:49.020 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.BeanNameViewResolver : No matching bean found for view name 'welcome'
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.b.f.s.DefaultListableBeanFactory : Invoking afterPropertiesSet() on bean with name 'welcome'
2016-04-24 19:54:49.022 TRACE 7880 --- [nio-8080-exec-1] o.s.w.s.v.InternalResourceViewResolver : Cached view [welcome]
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.s.v.ContentNegotiatingViewResolver : Returning [org.springframework.web.servlet.view.InternalResourceView: name 'welcome'; URL [/WEB-INF/jsp/welcome.jsp]] based on requested media type 'text/html'
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.web.servlet.DispatcherServlet : Rendering view [org.springframework.web.servlet.view.InternalResourceView: name 'welcome'; URL [/WEB-INF/jsp/welcome.jsp]] in DispatcherServlet with name 'dispatcherServlet'
2016-04-24 19:54:49.022 TRACE 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.InternalResourceView : Rendering view with name 'welcome' with model {} and static attributes {}
2016-04-24 19:54:49.026 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.InternalResourceView : Forwarding to resource [/WEB-INF/jsp/welcome.jsp] in InternalResourceView 'welcome'
2
As you see in the trace, this is trying to resolve /jsp/welcome.jsp as InternalResourceView instead of JstlView. Eventually it fails as 404.
正如您在跟踪中看到的，这试图将 /jsp/welcome.jsp 解析为 InternalResourceView 而不是 JstlView。最终它以 404 失败。
What other steps I need to follow? Is there any tutorial for SpringBoot-mvc with jsp ?
我还需要遵循哪些其他步骤？有没有关于带有 jsp 的 SpringBoot-mvc 的教程？
P.S. I can create spring mvc app with jsp using web.xml ( using JstlView in my config file ). But I can't find any tutorial for Spring boot mvc with jsp.
PS我可以使用web.xml（在我的配置文件中使用JstlView）用jsp创建spring mvc应用程序。但是我找不到任何关于带有 jsp 的 Spring boot mvc 的教程。
回答by sura2k
Assuming it is embedded Tomcat,
假设它是嵌入式Tomcat，
You need to have followings in your pom.xml
你需要在你的 pom.xml
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
Embedded Tomcat core package has no JSP rendering support.
嵌入式 Tomcat 核心包没有 JSP 渲染支持。
回答by Yura
@Bean
public ViewResolver getViewResolver(){
InternalResourceViewResolver resolver = new InternalResourceViewResolver();
resolver.setPrefix("/WEB-INF/jsp/");
resolver.setSuffix(".jsp");
resolver.setViewClass(JstlView.class);
return resolver;
}
also needed and your pages should be at /webapp/WEB-INF/jsp/
也需要，你的页面应该在 /webapp/WEB-INF/jsp/
+
+
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-tomcat</artifactId>
</dependency>
<dependency>
<groupId>org.apache.tomcat.embed</groupId>
<artifactId>tomcat-embed-jasper</artifactId>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>jstl</artifactId>
</dependency>
回答by AlphaAtlas
You do not require the ViewResolver. pom.xml needs the mentioned dependencies as told by Yura and place the jsp files in src\main\webapp\WEB-INF\jsp.
您不需要 ViewResolver。pom.xml 需要上述提到的依赖项，如 Yura 所说，并将 jsp 文件放在 src\main\webapp\WEB-INF\jsp 中。
回答by Sudip_Rana
- Create webapp/WEB-INF/views {Name the last folder as U Like } under src/main
add jstl jar
add following two lines in application.properties
spring.mvc.view.prefix:/WEB-INF/views/ spring.mvc.view.suffix:.jsp
Run As Spring Boot App ..U are good to go !
For More U can consult my this project on github : https://github.com/SudipBiswasRana/Using-JSP-As-View-For-Spring-Project
- 在 src/main 下创建 webapp/WEB-INF/views {Name the last folder as U Like }
添加jstl jar
在 application.properties 中添加以下两行
spring.mvc.view.prefix:/WEB-INF/views/ spring.mvc.view.suffix:.jsp
Run As Spring Boot App ..U 很好！
更多你可以在github上咨询我的这个项目：https: //github.com/SudipBiswasRana/Using-JSP-As-View-For-Spring-Project
