Laravel 在视图中获取带参数的路由
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Laravel get route with parameter in view
提问by Marek123
I need to get the route in my view for redirecting.
我需要在我的视图中获取路线以进行重定向。
Right now I'm doing this:
Laravel 4 - Get Current Route Name on Hidden Input to use for search
现在我正在这样做：
Laravel 4 - 在隐藏输入上获取当前路线名称以用于搜索
{{ Form::hidden('route', Route::current()->getUri()) }}
Problem is, it looks like this when I get on a page with an id:
问题是，当我进入一个带有 id 的页面时，它看起来像这样：
<input name="route" type="hidden" value="recipes/details/{id}">
How can I parse the {id} variable?
如何解析 {id} 变量？
回答by The Alpha
You should use:
你应该使用：
Request::url();
Instead of Route::current()->getUri(), but it's not proper way to redirect from the View, you should redirect from your Controllerinstead.
代替 Route::current()->getUri()，但它不是从 重定向的正确方法View，您应该从您的Controller改为重定向。
It should be in your case (for full url):
它应该在您的情况下（对于完整网址）：
// 'http://example.com/recipes/details/10'
{{ Form::hidden('route', Request::url()) }}
or use this (only for path):
或使用此（仅用于路径）：
// 'recipes/details/10'
{{ Form::hidden('route', Request::path()) }}
