Linux 如何递归列出所有文件和目录
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How to recursively list all files and directories
提问by Ben
Using the tcsh shell on Free BSD, is there a way to recursively list all files and directories including the owner, group and relative path to the file?
在 Free BSD 上使用 tcsh shell，有没有办法递归列出所有文件和目录，包括所有者、组和文件的相对路径？
ls -alR comes close, but it does not show the relative path in front of every file, it shows the path at the top of a grouping i.e.
ls -alR 接近，但它没有在每个文件前面显示相对路径，它显示了分组顶部的路径，即
owner% ls -alR
total 0
drwxr-xr-x 3 owner group 102 Feb 1 10:50 .
drwx------+ 27 owner group 918 Feb 1 10:49 ..
drwxr-xr-x 5 owner group 170 Feb 1 10:50 subfolder
./subfolder:
total 16
drwxr-xr-x 5 owner group 170 Feb 1 10:50 .
drwxr-xr-x 3 owner group 102 Feb 1 10:50 ..
-rw-r--r-- 1 owner group 0 Feb 1 10:50 file1
-rw-r--r-- 1 owner group 0 Feb 1 10:50 file2
What I would like is output like:
我想要的是输出如下：
owner group ./relative/path/to/file
The accepted answer to this questionshows the relative path to a file, but does not show the owner and group.
采纳答案by James Brady
How about this:
这个怎么样：
find . -exec ls -dl \{\} \; | awk '{print , , }'
回答by Torsten Marek
findcomes close:
find接近：
find . -printf "%u %g %p\n"
There is also "%P", which removes the prefix from the filename, if you want the paths to be relative to the specified directory.
还有“%P”，如果您希望路径相对于指定目录，它会从文件名中删除前缀。
Note that this is GNU find, I don't know if the BSD find also supports -printf.
注意这是GNU find，不知道BSD find是否也支持-printf。
回答by Chris Lutz
Use a shell script. Or a Perl script. Example Perl script (because it's easier for me to do):
使用 shell 脚本。或 Perl 脚本。示例 Perl 脚本（因为我更容易做）：
#!/usr/bin/perl
use strict;
use warnings;
foreach(`find . -name \*`) {
chomp;
my $ls = `ls -l $_`;
# an incomprehensible string of characters because it's Perl
my($owner, $group) = /\S+\s+\S+\s+(\S+)\s+(\S)+/;
printf("%-10s %-10s %s\n", $owner, $group, $_);
}
Perhaps a bit more verbose than the other answers, but should do the trick, and should save you having to remember what to type. (Code untested.)
也许比其他答案更冗长，但应该可以解决问题，并且应该让您不必记住要键入的内容。（代码未经测试。）
回答by slim
If you fancy using Perl don't use it as a wrapper around shell commands. Doing it in native Perl is faster, more portable, and more resilient. Plus it avoids ad-hoc regexes.
如果您喜欢使用 Perl，请不要将其用作 shell 命令的包装器。在原生 Perl 中执行此操作更快、更便携且更有弹性。此外，它避免了临时正则表达式。
use File::Find;
use File::stat;
find (\&myList, ".");
sub myList {
my $st = lstat($_) or die "No $file: $!";
print getgrnam($st->gid), " ",
getpwuid($st->uid), " ",
$File::Find::name, "\n";
}
回答by Davide
Use tree. Few linux distributions install it by default (in these dark daysof only GUIs :-), but it's always available in the standard repositories. It should be available for *BSD also, see http://mama.indstate.edu/users/ice/tree/
使用树。很少有 Linux 发行版会默认安装它（在这些只有 GUI 的黑暗日子里：-），但它在标准存储库中始终可用。它也应该可用于 *BSD，请参阅http://mama.indstate.edu/users/ice/tree/
Use:
用：
tree -p -u -g -f -i
or
或者
tree -p -u -g -f
or check the man page for many other useful arguments.
或查看手册页以获取许多其他有用的参数。
回答by Andrew
You've already got an answer that works, but for reference you should be able to do this on the BSDs (I've tested it on a mac) :
您已经得到了一个有效的答案，但作为参考，您应该能够在 BSD 上执行此操作（我已经在 mac 上对其进行了测试）：
find . -ls
回答by Аз_10000
Works in Linux Debian:
适用于 Linux Debian：
find $PWD -type f
回答by Ajith H
Simple way I found was this:
我发现的简单方法是这样的：
ls -lthr /path_to_directory/*
ls -lthr /path_to_directory/*
" * " - represents levels.
“ * ” - 代表级别。
Ajiths-MBP:test ajith$ ls -lthr *
test2:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test2.txt
test3:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test3.txt
test1:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:21 test1.txt
drwxr-xr-x 3 ajith staff 96B Oct 17 18:22 test1_sub_dir
Ajiths-MBP:test ajith$ ls -lthr */*
-rw-r--r-- 1 ajith staff 0B Oct 17 18:21 test1/test1.txt
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test2/test2.txt
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test3/test3.txt
test1/test1_sub_dir:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test1_sub_file.txt
