javascript Nodejs - 迭代嵌套 JSON 数组的正确方法
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/22709354/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Nodejs - Correct way to iterate through nested JSON array
提问by fearhsonic
Consider the following sample JSON array:
考虑以下示例 JSON 数组：
[{
info: {
refOne: 'refOne',
refTwo: [{
refOne: 'refOne',
refTwo: 'refTwo'
}]
}
}, {
info: {
refOne: 'refOne',
refTwo: [{
refOne: 'refOne',
refTwo: 'refTwo'
}]
}
}]
The above JSON is a simple representation of a database query response, What is the correct way within Nodejs to loop through each 'refTwo' array within the parent info array?
上面的 JSON 是数据库查询响应的简单表示，Nodejs 中循环遍历父信息数组中的每个“refTwo”数组的正确方法是什么？
sudo example: for each item in sample JSON for each refTwo item in current item do something
sudo 示例：对于示例 JSON 中的每个项目，为当前项目中的每个 refTwo 项目做一些事情
I have a suspicion that the 'async' lib may be required here but some advice is much appreciated.
我怀疑这里可能需要“异步”库，但非常感谢一些建议。
回答by Gabriel Llamas
This is a simple javascript question:
这是一个简单的javascript问题：
var o = [...];
var fn = function (e){
e.refOne...
e.refTwo...
};
o.forEach (function (e){
e.info.refTwo.forEach (fn);
});
回答by Otze
You could use underscoreor lodashto do it in a functional way.
For example have a look at Collections.eachand Collections.map:
例如看看Collections.each和Collections.map：
var _ = require('underscore');
var result = // your json blob here
var myRefs = _.map(results, function(value, key) {
return value.info.refTwo;
};
// myRefs contains the two arrays from results[0].info.refTwo from results[1].info.refTwo now
// Or with each:
_.each(results, function(value, key) {
console.log(value.info.refTwo);
}
// Naturally you can nest, too:
_.each(results, function(value, key) {
_.each(value.info.refTwo, function(innerValue) { // the key parameter is optional
console.log(value);
}
}
Edit: You can of course use the forEach method suggested by Gabriel Llamas, however I'd recommend having a look at underscore nonetheless.
编辑：您当然可以使用 Gabriel Llamas 建议的 forEach 方法，但是我仍然建议您查看下划线。
