Linux 用气拼装时push指令后缀无效
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Invalid instruction suffix for push when assembling with gas
提问by vitaut
When assembling a file with GNU assembler I get the following error:
使用 GNU 汇编器组装文件时，出现以下错误：
hello.s:6: Error: invalid instruction suffix for `push'
hello.s:6: 错误：`push' 的指令后缀无效
Here's the file that I'm trying to assemble:
这是我试图组装的文件：
.text
LC0:
.ascii "Hello, world!movl , %eax # 32-bit instruction
movq , %rax # 64-bit instruction
pushl %eax # Illegal instruction
pushq %rax # 1 byte instruction encoded as pushl %eax in 32 bits
pushq %r10 # 2 byte instruction encoded as pushl preceeded by REX
"
.globl _main
_main:
pushl %ebp
movl %esp, %ebp
subl , %esp
andl $-16, %esp
movl example.s:6:suffix or operands invalid for `push'
, %eax
movl %eax, -4(%ebp)
movl -4(%ebp), %eax
call __alloca
call ___main
movl $LC0, (%esp)
call _printf
movl ##代码##, %eax
leave
ret
What is wrong here and how do I fix it?
这里有什么问题，我该如何解决？
The problem is somewhat related to this questionalthough errors and instructions in questions are different.
采纳答案by Anu
64bit instructions
64位指令
By default most operations remain 32-bit and the 64-bit counterparts are invoked by the fourth bit in the REX prefix. This means that each 32-bit instruction has it's natural 64-bit extension and that extended registers are for free in 64-bit instructions
默认情况下，大多数操作保持 32 位，而 64 位对应操作由 REX 前缀中的第四位调用。这意味着每条 32 位指令都有其自然的 64 位扩展，并且扩展寄存器在 64 位指令中是免费的
##代码##回答by Carl Norum
Are you assembling with a 64-bit assembler? Your code looks like it's 32-bit. I get this error with your code when using a 64-bit assembler:
你是用 64 位汇编器组装的吗？您的代码看起来像是 32 位的。使用 64 位汇编器时，我的代码出现此错误：
##代码##But it works fine with a 32-bit assembler.
但它在 32 位汇编器上运行良好。
回答by rem
You have to use a "64 bit syntax", or you can use the " --32 " option: by this way the assembler chages its target to the i386 platform.
您必须使用“64 位语法”，或者您可以使用“--32”选项：通过这种方式，汇编器将其目标更改为 i386 平台。
回答by Xiao Jia
Prepend .code32as your first line.
前置.code32为您的第一道防线。
--32option will change the target to 32 bit platform.
--32选项会将目标更改为 32 位平台。
