Java ArrayList<String> 到 CharSequence[]
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ArrayList<String> to CharSequence[]
提问by Laimoncijus
What would be the easiest way to make a CharSequence[]out of ArrayList<String>?
最简单的方法CharSequence[]是ArrayList<String>什么？
Sure I could iterate through every ArrayListitem and copy to CharSequencearray, but maybe there is better/faster way?
当然我可以遍历每个ArrayList项目并复制到CharSequence数组，但也许有更好/更快的方法？
采纳答案by BalusC
You can use List#toArray(T[])for this.
您可以List#toArray(T[])为此使用。
CharSequence[] cs = list.toArray(new CharSequence[list.size()]);
Here's a little demo:
这是一个小演示：
List<String> list = Arrays.asList("foo", "bar", "waa");
CharSequence[] cs = list.toArray(new CharSequence[list.size()]);
System.out.println(Arrays.toString(cs)); // [foo, bar, waa]
回答by seh
Given that type Stringalready implements CharSequence, this conversion is as simple as asking the list to copy itself into a fresh array, which won't actually copy any of the underlying character data. You're just copying references to Stringinstances around:
鉴于该类型String已经实现了CharSequence，这种转换就像要求列表将自身复制到一个新数组中一样简单，它实际上不会复制任何底层字符数据。您只是复制对String周围实例的引用：
final CharSequence[] chars = list.toArray(new CharSequence[list.size()]);
