Bash 脚本将 cat 输出存储在变量中，然后回显它
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Bash Script store cat output in variable and then echo it
提问by Sumeet Masih
I am trying to store a cat output into a variable and then trying to echo it. and then I would like to kill the process.
我正在尝试将 cat 输出存储到一个变量中，然后尝试对其进行回显。然后我想终止这个进程。
#!/bin/bash
var = $(cat tmp/pids/unicorn.pid)
echo $var
sudo kill -QUIT $var
Please if anyone can tell where I am going wrong
请如果有人能告诉我哪里出错了
回答by user000001
Variable assignments in bash should not have any spaces before or after the equal sign. It should be like this:
bash 中的变量赋值不应在等号前后有任何空格。应该是这样的：
#!/bin/bash
var=$(cat tmp/pids/unicorn.pid)
echo "$var"
Which can be written more idiomatically as
哪个可以更惯用地写成
#!/bin/bash
var=$(< tmp/pids/unicorn.pid)
echo "$var"
