javascript jQuery 查找所有以定义的字符串开头并以数字结尾的 id
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jQuery find all id's that begin with a defined string and end in a number
提问by Chris Dutrow
I would like to do something like this:
我想做这样的事情：
jqueryElement.find('divIdWithIterator**').each(...);
where 'divIdWithIterator**'matches all elements with ids that start with 'divIdWithIterator'and end in a number, such as:
where'divIdWithIterator**'匹配所有 id 以数字开头'divIdWithIterator'和结尾的元素，例如：
divIdWithIterator1, divIdWithIterator2, divIdWithIterator26
divIdWithIterator1, divIdWithIterator2, divIdWithIterator26
What is a good way to do this in jQuery?
在 jQuery 中执行此操作的好方法是什么？
Thanks!
谢谢！
回答by Phil
Unfortunately, there is no regular expression selector.
不幸的是，没有正则表达式选择器。
You could use the attribute-starts-with selector, then filterthe results and check for numeric endings using search()
您可以使用attribute-starts-with 选择器，然后过滤结果并使用检查数字结尾search()
Eg
例如
var divs = jqueryElement.find('[id^="divIdWithIterator"]').filter(function(index){
return this.id.search(/\d$/) != -1;
});
回答by ariel
Following: http://api.jquery.com/attribute-starts-with-selector/
以下：http: //api.jquery.com/attribute-starts-with-selector/
To find the elements whose id begin with "divIdWithIterator":
要查找 id 以“divIdWithIterator”开头的元素：
$('input[id^="divIdWithIterator"]')
And then avoid to have other elements that begin with "divIdWithIterator" and you don't want to select
然后避免有其他以“divIdWithIterator”开头的元素并且您不想选择
