带有 if 语句的 Javascript while 循环
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Javascript while loop with if statements
提问by Dolbyover
I am trying to create a while loop in Javascript. I have a an array called numbers that contains 5 numbers. I also have a variable called bigone that is set to 0. I am trying to write a while loop that has an if statement that compares each value in the array to bigone. When the number in the array slot is greater then bigone, I want to assign that number to bigone. I cant figure it out. Here is what I have so far but it wont work. Yes this is homework and NO I am not asking for the answer, just for some guidance in the right direction. Here is as far as I have gotten :
我正在尝试在 Javascript 中创建一个 while 循环。我有一个名为 numbers 的数组，其中包含 5 个数字。我还有一个名为 bigone 的变量，它设置为 0。我正在尝试编写一个 while 循环，该循环具有一个 if 语句，用于将数组中的每个值与 bigone 进行比较。当数组槽中的数字大于 bigone 时，我想将该数字分配给 bigone。我想不通。这是我到目前为止所拥有的，但它不起作用。是的，这是家庭作业，不，我不是在要求答案，只是为了一些正确方向的指导。这是我所得到的：
while ( numbers.length < 5 ) {
if ( numbers > bigone ) {
bigone = numbers
}
}
Any ideas?
有任何想法吗？
采纳答案by SimonDever
Implement a counter so you can access the values in the array.
实现一个计数器，以便您可以访问数组中的值。
var i = 0;
while(numbers.length < 5 && i < numbers.length)
{
if(numbers[i] > bigone)
bigone = numbers[i];
i++;
}
This is the same loop but with for. Not sure why you are checking if there are 5 or less elements in the array but ok. This checks the length on every iteration.
这是相同的循环，但使用for. 不知道为什么要检查数组中是否有 5 个或更少的元素，但没问题。这会检查每次迭代的长度。
for(var i = 0; numbers.length < 5 && i < numbers.length; i++)
{
if(numbers[i] > bigone)
bigone = numbers[i];
}
A better method to just check it once is to wrap the forloop in an ifstatement like this:
仅检查一次的更好方法是将for循环包装在如下if语句中：
if(numbers.length < 5)
{
for(var i = 0; i < numbers.length; i++)
{
if(numbers[i] > bigone)
bigone = numbers[i];
}
}
回答by c.P.u1
I presume you are trying to find the largest number in the array. Another way to do this is to use the forEach method, which takes a callback function as an argument. The callback is executed once for each element of the array.
我假设您正在尝试在数组中找到最大的数字。另一种方法是使用 forEach 方法，该方法将回调函数作为参数。回调对数组的每个元素执行一次。
var numbers = [4, 12, 3, 5, 1]
var big = 0;
numbers.forEach(function(number) { if(number > big) big = number; });
console.log(big); //Prints 12
