C# 如何形成正确的 MySQL 连接字符串?

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时间:2020-08-09 14:07:20  来源:igfitidea点击:

How to form a correct MySQL connection string?

c#mysqldatabase-connection

提问by user123_456

I am using C# and I am trying to connect to the MySQL database hosted by 00webhost.

我正在使用 C# 并且我正在尝试连接到由 00webhost 托管的 MySQL 数据库。

I am getting error on the line connection.Open():

我在线上收到错误connection.Open()

there is no mysql host with this parameters.

没有带有此参数的 mysql 主机。

I have checked and everything seems to be fine.

我已经检查过,一切似乎都很好。

string MyConString = "SERVER=mysql7.000webhost.com;" +
        "DATABASE=a455555_test;" +
        "UID=a455555_me;" +
        "PASSWORD=something;";
         MySqlConnection connection = new MySqlConnection(MyConString);
         MySqlCommand command = connection.CreateCommand();
         MySqlDataReader Reader;
         command.CommandText = "INSERT Test SET lat=" + 
             OSGconv.deciLat + ",long=" + OSGconv.deciLon;
         connection.Open();
         Reader = command.ExecuteReader();
         connection.Close();

What is wrong with this connection string?

这个连接字符串有什么问题?

采纳答案by laltin

try creating connection string this way:

尝试以这种方式创建连接字符串:

MySqlConnectionStringBuilder conn_string = new MySqlConnectionStringBuilder();
conn_string.Server = "mysql7.000webhost.com";
conn_string.UserID = "a455555_test";
conn_string.Password = "a455555_me";
conn_string.Database = "xxxxxxxx";

using (MySqlConnection conn = new MySqlConnection(conn_string.ToString()))
using (MySqlCommand cmd = conn.CreateCommand())
{    //watch out for this SQL injection vulnerability below
     cmd.CommandText = string.Format("INSERT Test (lat, long) VALUES ({0},{1})",
                                    OSGconv.deciLat, OSGconv.deciLon);
     conn.Open();
     cmd.ExecuteNonQuery();
}

回答by digitalmarks

string MyConString = "Data Source='mysql7.000webhost.com';" +
"Port=3306;" +
"Database='a455555_test';" +
"UID='a455555_me';" +
"PWD='something';";

回答by Hiren

Here is an example:

下面是一个例子:

MySqlConnection con = new MySqlConnection(
    "Server=ServerName;Database=DataBaseName;UID=username;Password=password");

MySqlCommand cmd = new MySqlCommand(
    " INSERT Into Test (lat, long) VALUES ('"+OSGconv.deciLat+"','"+
    OSGconv.deciLon+"')", con);

con.Open();
cmd.ExecuteNonQuery();
con.Close();