Python 如何检查变量的类型是否为字符串？
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How to check if type of a variable is string?
提问by c_pleaseUpvote
Is there a way to check if the type of a variable in python is a string, like:
有没有办法检查python中变量的类型是否为 a string，例如：
isinstance(x,int);
for integer values?
对于整数值？
回答by Sven Marnach
In Python 2.x, you would do
在 Python 2.x 中，你会做
isinstance(s, basestring)
basestringis the abstract superclassof strand unicode. It can be used to test whether an object is an instance of stror unicode.
basestring是抽象的超类的str和unicode。它可用于测试对象是否是str或的实例unicode。
In Python 3.x, the correct test is
在 Python 3.x 中，正确的测试是
isinstance(s, str)
The bytesclass isn't considered a string type in Python 3.
本bytes类不被认为是在Python 3字符串类型。
回答by dicato
The type module also exists if you are checking more than ints and strings. http://docs.python.org/library/types.html
如果您检查的不仅仅是整数和字符串，类型模块也存在。 http://docs.python.org/library/types.html
回答by Wade Hatler
Edit based on better answer below. Go down about 3 answers and find out about the coolness of basestring.
根据下面更好的答案进行编辑。往下看大约 3 个答案，了解 basestring 的酷炫。
Old answer: Watch out for unicode strings, which you can get from several places, including all COM calls in Windows.
旧答案：注意 unicode 字符串，您可以从多个地方获取它，包括 Windows 中的所有 COM 调用。
if isinstance(target, str) or isinstance(target, unicode):
回答by yprez
Alternative way for Python 2, without using basestring:
Python 2 的替代方法，不使用 basestring：
isinstance(s, (str, unicode))
But still won't work in Python 3 since unicodeisn't defined (in Python 3).
但仍然不能在 Python 3 中工作，因为unicode没有定义（在 Python 3 中）。
回答by Daniil Grankin
Also I want notice that if you want to check whether the type of a variable is a specific kind, you can compare the type of the variable to the type of a known object.
另外我要注意的是，如果您想检查变量的类型是否为特定类型，您可以将变量的类型与已知对象的类型进行比较。
For string you can use this
对于字符串，您可以使用它
type(s) == type('')
回答by André Fratelli
I know this is an old topic, but being the first one shown on google and given that I don't find any of the answers satisfactory, I'll leave this here for future reference:
我知道这是一个古老的话题，但作为第一个在 google 上显示的话题，鉴于我没有找到任何令人满意的答案，我将其留在这里以供将来参考：
sixis a Python 2 and 3 compatibility library which already covers this issue. You can then do something like this:
Six是一个 Python 2 和 3 兼容性库，它已经涵盖了这个问题。然后你可以做这样的事情：
import six
if isinstance(value, six.string_types):
pass # It's a string !!
Inspecting the code, this is what you find:
检查代码，这就是你发现的：
import sys
PY3 = sys.version_info[0] == 3
if PY3:
string_types = str,
else:
string_types = basestring,
回答by mPrinC
If you do not want to depend on external libs, this works both for Python 2.7+ and Python 3 (http://ideone.com/uB4Kdc):
如果您不想依赖外部库，这适用于 Python 2.7+ 和 Python 3 ( http://ideone.com/uB4Kdc)：
# your code goes here
s = ["test"];
#s = "test";
isString = False;
if(isinstance(s, str)):
isString = True;
try:
if(isinstance(s, basestring)):
isString = True;
except NameError:
pass;
if(isString):
print("String");
else:
print("Not String");
回答by User
This is how I do it:
这就是我的做法：
if type(x) == type(str()):
回答by fast tooth
I've seen:
我见过：
hasattr(s, 'endswith')
回答by Texom512
In Python 3.x or Python 2.7.6
在 Python 3.x 或 Python 2.7.6 中
if type(x) == str:
