php 通过 Laravel 中的链接 href 传递 id
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Passing id through an link href in Laravel
提问by steven
is it possible to pass id through an link href in Laravel and display that page like /projects/display/2.
是否可以通过 Laravel 中的链接 href 传递 id 并显示该页面，如 /projects/display/2。
I have this link:
我有这个链接：
<td><a href="{{ url('projects/display', $projects->id) }}" class="btn btn-info">View</a></td>
It displays the id when hovering over the link as /projects/display/2. But whenever i click on the link i get an error message of:
将鼠标悬停在链接上时，它将 id 显示为 /projects/display/2。但是每当我点击链接时，我都会收到一条错误消息：
Sorry, the page you are looking for could not be found.
I have a view setup called projects/display, plus routes and controller.
我有一个名为项目/显示的视图设置，以及路由和控制器。
routes:
路线：
<?php
Route::group(['middleware' => ['web']], function (){
Route::get('/', 'PagesController@getIndex');
Route::get('/login', 'PagesController@getLogin');
Auth::routes();
Route::get('/home', 'HomeController@index');
Route::get('/projects/display', 'ProjectsController@getDisplay');
Route::resource('projects', 'ProjectsController');
});
Controller:
控制器：
<?php
namespace App\Http\Controllers;
use App\project;
use App\Http\Requests;
use Illuminate\Http\Request;
use Session;
class ProjectsController extends Controller
{
public function index()
{
}
public function create()
{
return view('projects.create');
}
public function store(Request $request)
{
$this->validate($request, array(
'name' => 'required|max:200',
'description' => 'required'
));
$project = new project;
$project->name = $request->name;
$project->description = $request->description;
$project->save();
Session::flash('success', 'The project was successfully created!');
return redirect()->route('projects.show', $project->id);
}
public function show()
{
$project = Project::all();
return view('projects.show')->withProject($project);
}
public function edit($id)
{
//
}
public function update(Request $request, $id)
{
//
}
public function getDisplay($id){
$project = Project::find($id);
return view('projects/display')->withProject($project);
}
}
回答by Alexey Mezenin
You need to change your route to:
您需要将路线更改为：
Route::get('/projects/display/{id}', 'ProjectsController@getDisplay');
And then generate URL with:
然后使用以下命令生成 URL：
{{ url('projects/display/'.$projects->id) }}
回答by Harsha Sharan
If you write route like below,
如果你像下面这样写路由，
Route::get('/projects/display/{projectId}', 'ProjectsController@getDisplay')->name('displayProject');
You can use the name 'displayProject' in the href and pass the id as Array :
您可以在 href 中使用名称“displayProject”并将 id 作为 Array 传递：
<td><a href="{{ route('displayProject', ['projects' => $projects->id]) }}" class="btn btn-info">View</a></td>
回答by Daan Meijer
What you are looking for is a parameterized route. Read more about them here: https://laravel.com/docs/5.3/routing#required-parameters
您正在寻找的是参数化路由。在此处阅读有关它们的更多信息：https: //laravel.com/docs/5.3/routing#required-parameters
