C++ 如何完全禁用对 assert() 的调用？
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How can I completely disable calls to assert()?
提问by Abruzzo Forte e Gentile
My code is full of calls to assert(condition).
In the debug version I use g++ -gwhich triggers my assertions.
Unexpectedly, the same assertions are also triggered in my release version, the one compiled without -goption.
我的代码充满了对assert(condition). 在我使用的调试版本中g++ -g，它触发了我的断言。出乎意料的是，在我的发布版本中也触发了相同的断言，即没有-g选项编译的版本。
How can I completely disable my assertions at compile time? Should I explicitly define NDEBUGin any build I produce regardless of whether they are debug, release or anything else?
如何在编译时完全禁用我的断言？我是否应该NDEBUG在我生成的任何构建中明确定义，而不管它们是调试、发布还是其他任何东西？
回答by GWW
You must #define NDEBUG(or use the flag -DNDEBUGwith g++) this will disable assert as long as it's defined before the inclusion of the assert header file.
您必须#define NDEBUG（或使用-DNDEBUG带有g++的标志）这将禁用断言，只要它是在包含断言头文件之前定义的。
回答by Prasoon Saurav
Use #define NDEBUG
用 #define NDEBUG
7.2 Diagnostics
1 The header de?nes the assertmacro and refers to another macro,
NDEBUG
which is not de?ned by
<assert.h>. If NDEBUGis de?ned as a macro name at the point in the source ?le where is included, the assertmacro is de?ned simply as
#define assert(ignore) ((void)0)The assertmacro is rede?ned according to the current state of NDEBUGeach time that
<assert.h>is included.
7.2 诊断
1 头文件定义了assert宏并引用了另一个宏，
调试
哪个不是由 定义的
<assert.h>。如果NDEBUG在源文件中包含的点处定义为宏名称，则断言宏定义为
#define assert(ignore) ((void)0)该断言宏是雷德？根据当前状态定义NDEBUG每个时间
<assert.h>被包括。
回答by dcn
You can either disable assertions completely by
您可以通过以下方式完全禁用断言
#define NDEBUG
#include <assert.h>
or you can set NDEBUG (via -DNDEBUG) in your makefile/build procedure depending on whether you want a productive or dev version.
或者你可以在你的 makefile/build 过程中设置 NDEBUG（通过 -DNDEBUG），这取决于你想要一个生产版本还是开发版本。
回答by Alnitak
The -gflag doesn't affect the operation of assert, it just ensures that various debugging symbols are available.
该-g标志不影响 的操作assert，它只是确保各种调试符号可用。
Setting NDEBUGis the standard (as in official, ISO standard) way of disabling assertions.
设置NDEBUG是禁用断言的标准（如官方的 ISO 标准）方式。
回答by Fred Foo
Yes, define NDEBUGon the command line/build system with the preprocessor/compiler option -DNDEBUG.
是的，NDEBUG使用预处理器/编译器选项在命令行/构建系统上定义-DNDEBUG。
This has nothing to do with the debugging info inserted by -g.
这与插入的调试信息无关-g。
