在 C++ 中从标准输入读取
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reading from stdin in c++
提问by krisdigitx
I am trying to read from stdin using C++, using this code
我正在尝试使用 C++ 从标准输入读取，使用此代码
#include <iostream>
using namespace std;
int main() {
while(cin) {
getline(cin, input_line);
cout << input_line << endl;
};
return 0;
}
when i compile, i get this error..
当我编译时，我收到此错误..
[root@proxy-001 krisdigitx]# g++ -o capture -O3 capture.cpp
capture.cpp: In function aint main()a:
capture.cpp:6: error: ainput_linea was not declared in this scope
Any ideas whats missing?
任何想法缺少什么？
回答by loganfsmyth
You have not defined the variable input_line.
您尚未定义变量input_line。
Add this:
添加这个：
string input_line;
And add this include.
并添加这个包括。
#include <string>
Here is the full example. I also removed the semi-colon after the while loop, and you should have getlineinside the while to properly detect the end of the stream.
这是完整的示例。我还在 while 循环之后删除了分号，您应该getline在 while 内正确检测流的结尾。
#include <iostream>
#include <string>
int main() {
for (std::string line; std::getline(std::cin, line);) {
std::cout << line << std::endl;
}
return 0;
}
