Android 如何在另一个应用程序中启动活动？
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How to start activity in another application?
提问by user256239
I have application A defined as below:
我的应用程序 A 定义如下：
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name="com.example.MyExampleActivity"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
Now in application B, how can I write the code to start the activity in application A? Thanks!
现在在应用程序 B 中，如何编写代码来启动应用程序 A 中的活动？谢谢！
回答by user256239
If you guys are facing "Permission Denial: starting Intent..." error or if the app is getting crash without any reason during launching the app - Then use this single line code in Manifest
如果你们面临“权限拒绝：启动意图...”错误，或者应用程序在启动应用程序期间无故崩溃 - 然后在清单中使用此单行代码
android:exported="true"
Please be careful with finish(); , if you missed out it the app getting frozen. if its mentioned the app would be a smooth launcher.
请小心完成(); ，如果你错过了它，应用程序就会被冻结。如果提到该应用程序将是一个流畅的启动器。
finish();
The other solution only works for two activities that are in the same application. In my case, application B doesn't know class com.example.MyExampleActivity.classin the code, so compile will fail.
另一种解决方案仅适用于同一应用程序中的两个活动。就我而言，应用程序 B 不知道com.example.MyExampleActivity.class代码中的类，因此编译将失败。
I searched on the web and found something like this below, and it works well.
我在网上搜索，发现了下面这样的东西，而且效果很好。
Intent intent = new Intent();
intent.setComponent(new ComponentName("com.example", "com.example.MyExampleActivity"));
startActivity(intent);
You can also use the setClassName method:
您还可以使用 setClassName 方法：
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName("com.hotfoot.rapid.adani.wheeler.android", "com.hotfoot.rapid.adani.wheeler.android.view.activities.MainActivity");
startActivity(intent);
finish();
You can also pass the values from one app to another app :
您还可以将值从一个应用程序传递到另一个应用程序：
Intent launchIntent = getApplicationContext().getPackageManager().getLaunchIntentForPackage("com.hotfoot.rapid.adani.wheeler.android.LoginActivity");
if (launchIntent != null) {
launchIntent.putExtra("AppID", "MY-CHILD-APP1");
launchIntent.putExtra("UserID", "MY-APP");
launchIntent.putExtra("Password", "MY-PASSWORD");
startActivity(launchIntent);
finish();
} else {
Toast.makeText(getApplicationContext(), " launch Intent not available", Toast.LENGTH_SHORT).show();
}
回答by azelez
If both application have the same signature (meaning that both APPS are yours and signed with the same key), you can call your other app activity as follows:
如果两个应用程序具有相同的签名（意味着两个应用程序都是您的并且使用相同的密钥签名），您可以按如下方式调用您的其他应用程序活动：
Intent LaunchIntent = getActivity().getPackageManager().getLaunchIntentForPackage(CALC_PACKAGE_NAME);
startActivity(LaunchIntent);
Hope it helps.
希望能帮助到你。
