java 通过java连接到ftps站点

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/5825050/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-30 12:58:11  来源:igfitidea点击:

connect to ftps site via java

javaftpftp-clientftpsapache-commons-net

提问by Vivek

I am trying to connect to a clients ftps server via my java code. I am using apache commons library to do so. However, I am not able to do so. Can anyone please help me with this.

我正在尝试通过我的 java 代码连接到客户端 ftps 服务器。我正在使用 apache 公共库来这样做。但是,我无法这样做。任何人都可以帮我解决这个问题。

The client server uses FTPS/Implicit SSL connection and uses Passive mode for data Connections.

客户端服务器使用 FTPS/隐式 SSL 连接,并使用被动模式进行数据连接。

My code is as follows:

我的代码如下:

public static void connectServer(String host, int port, String userName, String password) throws Exception {
    FTPSClient client = new FTPSClient("SSL", true);
    String remote = "Contact.xml";

    File inFile = new File("C:/Documents/Applications/Contact.xml");
    File outFile = new File("C:/Documents/Applications/Sample.xml");

    InputStream input = new FileInputStream(inFile);
    InputStream out = new FileInputStream(outFile);

    try {

        if(client.isConnected()){
            client.disconnect();
        }

        client.connect(host,990);
        client.enterLocalPassiveMode();
        client.enterRemotePassiveMode();

        client.login(userName, password);

        client.setBufferSize((int)inFile.length()+100);
        client.completePendingCommand();

        System.out.println(client.printWorkingDirectory());
        System.out.println(inFile.getAbsolutePath());

        client.storeFile(remote, input);
        out = client.retrieveFileStream("/folder/inputfeed.xml");

        client.completePendingCommand();
        client.logout();

    } catch (Exception e) {
    e.printStackTrace();
        System.err.println(client.getReplyString());

    } finally {
        out.close();
        input.close();
        client.disconnect();
    }
}

This code does not throw any exception, but I don't see the file being copied to server, neither any data being copied to my InputStream. Also, sysout statement for getting the working directory returns me the correct directory. I am also able to connect to server via Filezilla and WinSCP.

此代码不会引发任何异常,但我没有看到文件被复制到服务器,也没有任何数据被复制到我的 InputStream。此外,用于获取工作目录的 sysout 语句会返回正确的目录。我还可以通过 Filezilla 和 WinSCP 连接到服务器。

Please help, I am getting stuck with this.

请帮忙,我被这个卡住了。

Thanks

谢谢

回答by Vladimir Dyuzhev

Why are you entering passive mode before login()?

为什么在 login() 之前进入被动模式?

I suspect that could be the issue, because the symptoms are those of active mode, where the connection cannot be established due to FW rule DROP (not REJECT; when rejected the exception is thrown right away, but DROP can hang forever).

我怀疑这可能是问题所在,因为症状是活动模式的症状,由于 FW 规则 DROP(不是 REJECT;拒绝时立即抛出异常,但 DROP 可以永远挂起),无法建立连接。

P.S. Also, not clear what is "remote" passive mode; the only one that makes difference is "local".

PS 另外,不清楚什么是“远程”被动模式;唯一不同的是“本地”。

回答by jbak

enterRemotePassiveMode();is used only for server to server connections, not client to server. Remove that line.

enterRemotePassiveMode();仅用于服务器到服务器的连接,而不是客户端到服务器的连接。删除该行。

回答by sheu

client.connect(host,990);Why are using the hardcoded port number? I suggest you change this line to use the port number passed to you function/method

client.connect(host,990);为什么使用硬编码的端口号?我建议您更改此行以使用传递给您的函数/方法的端口号

For reasons that I did not have time to look at you code hangs and this line

由于我没有时间看你代码挂起和这一行的原因

  client.completePendingCommand();

before the server disconnects it. I am not sure if you are not getting the exception or you are just not waiting long enough for you code to throw the exception

在服务器断开连接之前。我不确定您是否没有收到异常,或者您只是没有等待足够长的时间让您的代码抛出异常

回答by Robert E

You need to check status after each client(socket)method. Especially after client.connect()and client.login().

您需要在每种client(socket)方法后检查状态。特别是在client.connect()和之后client.login()

Example:

例子:

client.connect(host, 990);
System.out.print(client.getReplyString());
...
client.login(username,password);
System.out.print(client.getReplyString());

If the method failed (error), the getReplyString()is usually very descriptive about what you did wrong.

如果方法失败(错误),getReplyString()通常会非常详细地说明您做错了什么。

回答by Ashish Shetkar

The Port Number you use for FTP - 21 and for SFTP is 22

您用于 FTP - 21 和 SFTP 的端口号是 22

I has some what same requirement , to download file from different servers , so some times i had to use 21 and some time 22 .

我有一些相同的要求,从不同的服务器下载文件,所以有时我不得不使用 21 和一些时间 22 。

I tried below approach

我尝试了以下方法

FTPClient ftpClient = new FTPClient();

        int port = 21;
        try {

            try{
                ftpClient.connect(serverName, port);
            }catch(Exception e){
                ftpClient.connect(serverName, 22);  
            }

                try {
            ftpClient.login(user, pass);
            ftpClient.enterLocalPassiveMode();
            ftpClient.setFileType(FTP.BINARY_FILE_TYPE);
            ftpClient.changeWorkingDirectory(workingDir);


            String fileName = "fileToDownLoad";

            File downloadFile = new File(fileName);

            OutputStream localOutputStream = new BufferedOutputStream(
                    new FileOutputStream(downloadFile));
            InputStream fptInputStream = ftpClient.retrieveFileStream(folder
                    + "/" + file);
            byte[] bytesArray = new byte[4096];
            int bytesRead = -1;
            while ((bytesRead = fptInputStream.read(bytesArray)) != -1) {
                localOutputStream.write(bytesArray, 0, bytesRead);
            }

            boolean success = ftpClient.completePendingCommand();
            if (success) {

            }
            localOutputStream.close();
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }

    }