在逻辑上组合布尔值列表的最“pythonic”方式是什么？
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What is the most 'pythonic' way to logically combine a list of booleans?
提问by BobC
I have a list of booleans I'd like to logically combine using and/or. The expanded operations would be:
我有一个布尔值列表，我想使用和/或逻辑组合。扩展的操作将是：
vals = [True, False, True, True, True, False]
# And-ing them together
result = True
for item in vals:
result = result and item
# Or-ing them together
result = False
for item in vals:
result = result or item
Are there nifty one-liners for each of the above?
以上每种都有漂亮的单衬吗？
采纳答案by NullUserException
See all(iterable):
Return
Trueif all elements of the iterableare true (or if the iterableis empty).
返回
True如果的所有元素 迭代是真实的（或者如果可迭代为空）。
And any(iterable):
Return
Trueif any element of the iterableis true. If the iterableis empty, returnFalse.
True如果迭代的任何元素为真，则 返回。如果可迭代对象为空，则返回False。
回答by Jerub
The best way to do it is with the any()and all()functions.
最好的方法是使用any()和all()函数。
vals = [True, False, True, True, True]
if any(vals):
print "any() reckons there's something true in the list."
if all(vals):
print "all() reckons there's no non-True values in the list."
if any(x % 4 for x in range(100)):
print "One of the numbers between 0 and 99 is divisible by 4."
