Javascript jQuery 每个表行中的循环

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时间:2020-08-24 01:17:03  来源:igfitidea点击:

jQuery each loop in table row

javascriptjqueryhtml-tableeachtablerow

提问by ANP

I am having something like:

我有这样的事情:

<table id="tblOne">
            <tbody>
                <tr>
                    <td>
                        <table id="tblTwo">
                            <tbody>
                                <tr>
                                    <td>
                                        Items
                                    </td>
                                </tr>
                                <tr>
                                    <td>
                                        Prod
                                    </td>
                                </tr>
                            </tbody>
                        </table>
                    </td>
                </tr>
                <tr>
                    <td>
                        Item 1
                    </td>
                </tr>
                <tr>
                    <td>
                        Item 2
                    </td>
                </tr>
            </tbody>
        </table>

I have written jQuery to loop through each tr like:

我已经编写了 jQuery 来循环遍历每个 tr,例如:

$('#tblOne tr').each(function() {...code...});

But problem is that it loops through the "tr" of "tblTwo" also which I don't want. Can anyone please suggest something to solve this?

但问题是它也循环了我不想要的“tblTwo”的“tr”。任何人都可以提出一些建议来解决这个问题吗?

回答by Fabrizio Calderan

In jQuery just use:

在 jQuery 中只需使用:

$('#tblOne > tbody  > tr').each(function() {...code...});

Using the children selector (>) you will walk over all the children (and not alldescendents), example with three rows:

使用子选择器 ( >) 您将遍历所有子项(而不是所有后代),例如三行:

$('table > tbody  > tr').each(function(index, tr) { 
   console.log(index);
   console.log(tr);
});

Result:

结果:

0
<tr>
1 
<tr>
2
<tr>


In VanillaJSyou can use document.querySelectorAll()and walk over the rows using forEach()

VanillaJS 中,您可以使用document.querySelectorAll()并遍历行forEach()

[].forEach.call(document.querySelectorAll('#tblOne > tbody  > tr'), function(index, tr) {
    /* console.log(index); */
    /* console.log(tr); */
});

回答by GNi33

Just a recommendation:

只是一个建议:

I'd recommend using the DOM table implementation, it's very straight forward and easy to use, you really don't need jQuery for this task.

我建议使用 DOM 表实现,它非常直接且易于使用,您真的不需要 jQuery 来完成这项任务。

var table = document.getElementById('tblOne');

var rowLength = table.rows.length;

for(var i=0; i<rowLength; i+=1){
  var row = table.rows[i];

  //your code goes here, looping over every row.
  //cells are accessed as easy

  var cellLength = row.cells.length;
  for(var y=0; y<cellLength; y+=1){
    var cell = row.cells[y];

    //do something with every cell here
  }
}

回答by Sarfraz

Use immediate children selector>:

使用直接子选择器>

$('#tblOne > tbody  > tr')

Description: Selects all direct child elementsspecified by "child" of elements specified by "parent".

描述:选择由“parent”指定的元素的“child”指定的所有直接子元素