javascript 错误：无法访问词法声明
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Error: Can't access lexical declaration
提问by Nona Haron
let textBytes = ctypes.uint8_t("hello");
let a = new SECItem;
a.type = siBuffer;
a.data = textBytes.address();
a.len = textBytes.length;
I got ReferenceError: can't access lexical declaration textBytes before initialization.
我得到了 ReferenceError: can't access lexical Declaration textBytes before Initialization。
回答by Noitidart
I can't reproduce the reference error you are getting, but I think change
我无法重现你得到的参考错误，但我认为改变
let textBytes = ctypes.uint8_t("hello");
as this throws TypeError: expected type uint8_t, got "hello"to
因为这将引发TypeError: expected type uint8_t, got "hello"对
let textBytes = ctypes.uint8_t.array()("hello");
This will give you a null-terminated string, of length 6. If you want it to be length 5, no null termination then do let textBytes = ctypes.uint8_t.array(5)("hello");
这将为您提供一个长度为 6 的空终止字符串。如果您希望它的长度为 5，则没有空终止然后执行 let textBytes = ctypes.uint8_t.array(5)("hello");
as I am thinking, change
正如我所想，改变
let a = new SECItem;
to
到
let a = SECItem();
or let a = new SECItem();they are both same.
或者let a = new SECItem();他们都是一样的。
If that doesn't fix it, please share the structure of SECItemand what is siBuffer.
如果不解决这个问题，请分享的结构SECItem，什么是siBuffer。
