Python 在 include() 中使用命名空间时关于 app_name 的 ImpropyConfiguredError
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ImpropyConfiguredError about app_name when using namespace in include()
提问by Nelson M
I am currently trying out django. I use the namespaceargument in one of my include()s in urls.py. When I run the server and try to browse,
I get this error.
我目前正在尝试 django。我在 urls.pynamespace中的一个include()s 中使用了该参数。当我运行服务器并尝试浏览时，出现此错误。
File "C:\Users\User\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\urls\conf.py", line 39, in include
'Specifying a namespace in include() without providing an app_name '
django.core.exceptions.ImproperlyConfigured: Specifying a namespace in include() without providing an app_name is not supported. Set the app_name attribute in the included module, or pass a 2-tuple containing the list of patterns and app_name instead.
These are my urls.py files:
这些是我的 urls.py 文件：
#project/urls.py
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^reviews/', include('reviews.urls', namespace='reviews')),
url(r'^admin/', include(admin.site.urls)),
]
and
和
#app/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
# ex: /
url(r'^$', views.review_list, name='review_list'),
# ex: /review/5/
url(r'^review/(?P<review_id>[0-9]+)/$', views.review_detail, name='review_detail'),
# ex: /wine/
url(r'^wine$', views.wine_list, name='wine_list'),
# ex: /wine/5/
url(r'^wine/(?P<wine_id>[0-9]+)/$', views.wine_detail, name='wine_detail'),
]
What do I pass the app_nameas stated in the error message?
我通过app_name错误消息中的说明传递了什么？
回答by unixia
回答by Bob
Django 1.11+, 2.0+
Django 1.11+、2.0+
You should set the app_name in the urls file you are including
您应该在包含的 urls 文件中设置 app_name
# reviews/urls.py <-- i.e. in your app's urls.py
app_name = 'reviews'
?
Then you can include it the way you are doing it.
然后你可以按照你的方式包含它。
Also, it might be worth noting what Django docs say here https://docs.djangoproject.com/en/1.11/ref/urls/#include:
此外，可能值得注意的是 Django 文档在这里说的https://docs.djangoproject.com/en/1.11/ref/urls/#include：
Deprecated since version 1.9: Support for the app_name argument is deprecated and will be removed in Django 2.0. Specify the app_name as explained in URL namespaces and included URLconfs instead.
1.9 版后已弃用：不推荐使用 app_name 参数，并将在 Django 2.0 中删除。按照 URL 命名空间中的说明指定 app_name，并改为包含 URLconf。
( https://docs.djangoproject.com/en/1.11/topics/http/urls/#namespaces-and-include)
（https://docs.djangoproject.com/en/1.11/topics/http/urls/#namespaces-and-include）
回答by Brayan Loayza
Django 2.0 you should specify app_namein your urls.py, is not necessary to specify app_name argument on include.
Django 2.0 你应该在你的urls.py 中指定app_name，不需要在 include 上指定 app_name 参数。
Main Url file.
主 URL 文件。
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('', include('apps.main.urls')),
path('admin/', admin.site.urls),
]
Included Url.
包含网址。
from django.urls import path
from . import views
app_name = 'main_app'
urlpatterns = [
path('', views.index, name='index'),
]
Then use use in template as
然后在模板中使用 use as
<a href="{% url main_app:index' %}"> link </a>
More details: https://code.djangoproject.com/ticket/28691Django 2.0 Docs
更多细节：https: //code.djangoproject.com/ticket/28691 Django 2.0 Docs
回答by Herbert
I included a library not (fully) django 2.1 compatible yet (django_auth_pro_saml2). Hence I create a second file saml_urls.py:
我包含了一个不（完全）与 django 2.1 兼容的库（django_auth_pro_saml2）。因此我创建了第二个文件saml_urls.py：
from django_saml2_pro_auth.urls import urlpatterns
app_name = 'saml'
Such that I could include the urls as:
这样我就可以将网址包括为：
from django.urls import include, re_path as url
urlpatterns = [
..., url(r'', include('your_app.saml_urls', namespace='saml')), ...
]
Hacky, but it worked for me, whereas the url(r'^reviews/', include(('reviews.urls', 'reviews'), namespace='reviews'))did not.
Hacky，但它对我有用，而url(r'^reviews/', include(('reviews.urls', 'reviews'), namespace='reviews'))没有。
回答by sayalok
I am also face the same error in Django 2.2and i solve it this way
我在Django 2.2 中也面临同样的错误，我是这样解决的
urls.py file
urls.py 文件
urlpatterns = [
path('publisher-polls/', include('polls.urls', namespace='publisher-polls')),
]
polls/urls.py file
polls/urls.py 文件
app_name = 'polls'
urlpatterns = [
path('', views.IndexView.as_view(), name='index')
]
example use of namespace in calss based view method
在基于 calss 的视图方法中使用命名空间的示例
def get_absolute_url(self):
from django.urls import reverse
return reverse('polls.index', args=[str(self.id)])
example use of namespace in templates
模板中命名空间的使用示例
{% url 'polls:index' %}
Here polls:indexmean app_name[define in polls/urls.py file]:name[define in polls/urls.py fileinside path function]
这里polls:index 的意思是 app_name[在polls/urls.py 文件中定义]:name[在polls/urls.py 文件中定义在path 函数中]
their official which is pretty good you can check for more info namespace_django_official_doc
他们的官方很不错，您可以查看更多信息namespace_django_official_doc
回答by coderanger
In my case, I was writing the urls outside the urlpatterns list. Please double check.
就我而言，我在 urlpatterns 列表之外编写了 url。请仔细检查。
