python re.split() 按空格、逗号和句点分割，但不是在 1,000 或 1.50 等情况下
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python re.split() to split by spaces, commas, and periods, but not in cases like 1,000 or 1.50
提问by rohanag
I want to use python re.split()to split a string into individual words by spaces, commas and periods. But I don't want "1,200"to be split into ["1", "200"]or ["1.2"]to be split into ["1", "2"].
我想使用 pythonre.split()按空格、逗号和句点将字符串拆分为单个单词。但我不想"1,200"被分裂成["1", "200"]或被["1.2"]分裂成["1", "2"].
Example
例子
l = "one two 3.4 5,6 seven.eight nine,ten"
The result should be ["one", "two", "3.4", "5,6" , "seven", "eight", "nine", "ten"]
结果应该是 ["one", "two", "3.4", "5,6" , "seven", "eight", "nine", "ten"]
采纳答案by Jo?o Silva
Use a negative lookahead and a negative lookbehind:
使用否定前瞻和否定后视：
> s = "one two 3.4 5,6 seven.eight nine,ten"
> parts = re.split('\s|(?<!\d)[,.](?!\d)', s)
['one', 'two', '3.4', '5,6', 'seven', 'eight', 'nine', 'ten']
In other words, you always split by \s(whitespace), and only split by commas and periods if they are notfollowed (?!\d)or preceded (?<!\d)by a digit.
换句话说，你总是用\s（空格）分割，如果后面或前面没有数字，则只用逗号和句点分割。(?!\d)(?<!\d)
DEMO.
演示。
EDIT: As per @verdesmarald comment, you may want to use the following instead:
编辑：根据@verdesmarald 评论，您可能希望使用以下内容：
> s = "one two 3.4 5,6 seven.eight nine,ten,1.2,a,5"
> print re.split('\s|(?<!\d)[,.]|[,.](?!\d)', s)
['one', 'two', '3.4', '5,6', 'seven', 'eight', 'nine', 'ten', '1.2', 'a', '5']
This will split "1.2,a,5"into ["1.2", "a", "5"].
这将拆分"1.2,a,5"为["1.2", "a", "5"].
DEMO.
演示。
回答by Niet the Dark Absol
So you want to split on spaces, and on commas and periods that aren't surrounded by numbers. This should work:
所以你想在空格、逗号和没有被数字包围的句点上拆分。这应该有效：
r" |(?<![0-9])[.,](?![0-9])"
