Javascript 如何从给定的模式开始删除字符串的结尾？
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How to remove the end of a string, starting from a given pattern?
提问by user765368
Let's say I have a string like this:
假设我有一个这样的字符串：
var str = "/abcd/efgh/ijkl/xxx-1/xxx-2";
How do I, using Javascript and/or jQuery, remove the part of strstarting with xxx, till the end of str?
我如何使用 Javascript 和/或 jQuery 删除从 ,str开始xxx到 结束的部分str？
回答by Will
str.substring( 0, str.indexOf( "xxx" ) );
回答by haylem
Just:
只是：
s.substring(0, s.indexOf("xxx"))
A safer version handling invalid input and lack of matching patterns would be:
处理无效输入和缺少匹配模式的更安全版本是：
function trump(str, pattern) {
var trumped = ""; // default return for invalid string and pattern
if (str && str.length) {
trumped = str;
if (pattern && pattern.length) {
var idx = str.indexOf(pattern);
if (idx != -1) {
trumped = str.substring(0, idx);
}
}
}
return (trumped);
}
which you'd call with:
你会打电话给：
var s = trump("/abcd/efgh/ijkl/xxx-1/xxx-2", "xxx");
回答by u283863
回答by Hemeligur
Try using string.slice(start, end):
尝试使用string.slice(start, end)：
If you know the exact number of characters you want to remove, from your example:
如果您知道要删除的确切字符数，请从示例中：
var str = "/abcd/efgh/ijkl/xxx-1/xxx-2";
new_str = str.slice(0, -11);
This would result in str_new == '/abcd/efgh/ijkl/'
这会导致 str_new == '/abcd/efgh/ijkl/'
Why this is useful:If the 'xxx'refers to any string (as the OP said), i.e: 'abc', '1k3', etc, andyou do not know beforehand what they could be (i.e: Not constant), the accepted answers, as well as most of the others will not work.
为什么这很有用：如果'xxx'指的是任何字符串（如 OP 所说），即：'abc'、'1k3' 等，并且您事先不知道它们可能是什么（即：不是常量），则接受的答案，以及其他大多数将不起作用。
回答by saluce
This will take everything from the start of the string to the beginning of xxx.
这将从字符串的开头到xxx.
str.substring(0,str.indexOf("xxx"));
