如何检查复选框是否在 PHP 中被选中？
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How do I check if checkbox is checked in PHP?
提问by Anders
I am trying to check if a checkbox have been checked in PHP in order to register. But it's not working right now. This is the code I am using so far, to check if it have been checked.
我正在尝试检查是否已在 PHP 中选中复选框以进行注册。但它现在不起作用。这是我目前使用的代码，用于检查它是否已被检查。
if(!isset($_POST['tos']))
$this->errors[] = 'Please accept our Terms of Service.';
And this is the HTML code.
这是 HTML 代码。
<div class="checkbox">
<label>
<input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
</label>
</div>
Full form code:
完整表格代码：
<form role="form" method="POST" action="<?php echo $_SERVER['PHP_SELF'];?>">
<div class="form-group">
<div class="row">
<div class="col-sm-6">
<label for="firstname">Firstname</label>
<input type="text" class="form-control" id="firstname" name="firstname" placeholder="Firstname">
</div>
<div class="col-sm-6">
<label for="surname">Surname</label>
<input type="text" class="form-control" id="surname" name="surname" placeholder="Surname">
</div>
</div>
</div>
<div class="form-group">
<label for="username">Username</label>
<input type="text" class="form-control" id="ruser" name="ruser" placeholder="Username">
</div>
<div class="form-group">
<label for="email2">Email address</label>
<input type="email" class="form-control" id="remail" name="remail" placeholder="Enter email">
</div>
<div class="form-group">
<div class="row">
<div class="col-sm-6">
<label for="password2">Password</label>
<input type="password" class="form-control" id="rpass" name="rpass" placeholder="Password">
</div>
<div class="col-sm-6">
<label for="password2">Repeat password</label>
<input type="password" class="form-control" id="rpass2" name="rpass2" placeholder="Password">
</div>
</div>
</div>
<div class="checkbox">
<label>
<input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
</label>
</div>
<input type="hidden" name="secur" value="<?php echo $ip;?>"/>
<input type="hidden" name="token" value="<?php echo $token;?>"/>
<button type="submit" name="register" class="btn btn-block btn-color btn-xxl">Create an account</button>
</form>
What's wrong with this code? Any help would be appreciated.
这段代码有什么问题？任何帮助，将不胜感激。
回答by Casey Dwayne
if(!isset($_POST['tos']))
$this->errors[] = 'Please accept our Terms of Service.';`
What this is doing is saying if there is no 'tos' in $_POST, throw an error.
这样做是说如果 $_POST 中没有“tos”，则抛出错误。
Really you should probably check this client side with javascript, beforethe form is sent to the server.
实际上，在将表单发送到服务器之前，您应该使用 javascript 检查此客户端。
You could also...
你也可以...
<input type="checkbox" name="tos" value="accepted" checked>
And PHP:
和 PHP：
if(isset($_POST['tos']) && $_POST['tos']==='accepted') echo 'All good';
else array_push($errors,'err code here'); //to add to $error array
Update
更新
I'm not sure if you're using jQuery or not, but just for a more user friendly approach:
我不确定您是否使用 jQuery，但只是为了更用户友好的方法：
var tos = $('#tos');
var notice = $('.notice');
tos.on('click',function(){
if(tos.is(':checked')){
notice.text('Thank you.');
}
else{
notice.text('Please accept our ToS to continue.');
}
})
See a working example here.You could even halt the form all together if it's unchecked. BTW, if I remember correctly checkboxinputs only send POST data ifchecked.
请参阅此处的工作示例。如果未选中，您甚至可以一起停止表单。顺便说一句，如果我没记错的话，checkbox输入只有在选中时才发送 POST 数据。
