java 如何获取hashmap对象值

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时间:2020-10-31 15:06:15  来源:igfitidea点击:

how to get hashmap object value

javaiteratorhashmap

提问by ishk

i have a code which put object as hashmap value. I want to read lat and lng from the hashmap using iterator class. But i dont know how to do this.here is my code.

我有一个将对象作为哈希映射值的代码。我想使用迭代器类从哈希图中读取 lat 和 lng。但我不知道该怎么做。这是我的代码。

Location locobj = new Location();
HashMap loc = new HashMap();

while(rs.next()){
      locobj.setLat(lat);
      locobj.setLng(lon);
      loc.put(location, locobj);

}

      Set set = loc.entrySet();
      Iterator i = set.iterator();
      while(i.hasNext()) {
      Map.Entry me = (Map.Entry)i.next();
      System.out.println(me.getKey()+"value>>"+me.getValue()); 
      }

class location is like this

上课地点是这样的

public class Location {

    private String lat;
    private String lng;
    private String name;

    public String getLat() {
        return lat;
    }
    public void setLat(String lat) {
        this.lat = lat;
    }
    public String getLng() {
        return lng;
    }
    public void setLng(String lng) {
        this.lng = lng;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }

}

how do i read locobj lat and lng value from getValue() method.please help

我如何从 getValue() 方法中读取 locobj lat 和 lng 值。请帮忙

回答by Manish Mulani

You should make use of generics here. Declare Map as

你应该在这里使用泛型。将地图声明为

Map<String, Location> locationMap = new HashMap<>() // assuming your key is of string type

That way, you can avoid typecasting (RTTI should be avoided - one of the design principles)

这样,您可以避免类型转换(应避免使用 RTTI - 设计原则之一)

Location locobj = me.getValue()
locobj.getLat() // will give you latitude
locobj.getLng() // will give you longitude

回答by DataNucleus

Why not just cast the value?

为什么不直接转换值?

Location locobj = (Location)me.getValue();
locobj.getLat();
locobj.getLng();

回答by Steve Atkinson

Change your code to use Generics.

更改您的代码以使用泛型。

Instead of

代替

Location locobj = new Location();
Map<Location> loc = new HashMap<Location>(); // code to interfaces, and use Generics

do

Location locobj = new Location();
HashMap<String,Location> loc = new HashMap<String,Location>();

and your entry as

和你的条目

Map.Entry<String,Location> me = (Map.Entry)i.next();

Then you won't have to cast anything

然后你就不必投射任何东西

回答by user3640657

The following can be used:

可以使用以下内容:

for (Entry entry : map.entrySet()) {
    String key = entry.getKey();
    Object values = (Object) entry.getValue();
    System.out.println("Key = " + key);
    System.out.println("Values = " + values + "n");
}

回答by Nikolay Kuznetsov

getValue()returns you reference to Object, but in fact object is Location. So you need to perform casting, see answer from @DataNucleus, but you can do even like this:

getValue()返回对 Object 的引用,但实际上 object 是 Location。因此,您需要执行转换,请参阅@DataNucleus 的答案,但您甚至可以这样做:

System.out.println(me.getKey()+"value>>"+((Location)me.getValue()).getLng()); 

回答by Kiran Mohan

You are retrieving an Object with getKey() or getValue(). You need to now call the getter methods to print the appropriate values.

您正在使用 getKey() 或 getValue() 检索对象。您现在需要调用 getter 方法来打印适当的值。