在 Python 中将浮点数列表转换为缓冲区？
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Convert list of floats into buffer in Python?
提问by okoman
I am playing around with PortAudio and Python.
我在玩 PortAudio 和 Python。
data = getData()
stream.write( data )
I want my stream to play sound data, that is represented in Float32 values. Therefore I use the following function:
我希望我的流播放声音数据，以 Float32 值表示。因此我使用以下功能：
def getData():
data = []
for i in range( 0, 1024 ):
data.append( 0.25 * math.sin( math.radians( i ) ) )
return data
Unfortunately that doesn't work because stream.writewants a buffer object to be passed in:
不幸的是，这不起作用，因为stream.write想要传入一个缓冲区对象：
TypeError: argument 2 must be string or read-only buffer, not list
So my question is: How can I convert my list of floats in to a buffer object?
所以我的问题是：如何将我的浮点数列表转换为缓冲区对象？
回答by Unknown
import struct
def getData():
data = []
for i in range( 0, 1024 ):
data.append( 0.25 * math.sin( math.radians( i ) ) )
return struct.pack('f'*len(data), *data)
回答by Christopher
Actually, the easiest way is to use the struct module. It is designed to convert from python objects to C-like "native" objects.
实际上，最简单的方法是使用struct 模块。它旨在从 python 对象转换为类似 C 的“本机”对象。
回答by Brian R. Bondy
Consider perhaps instead:
或许可以考虑一下：
d = [0.25 * math.sin(math.radians(i)) for i in range(0, 1024)]
Perhaps you have to use a package like pickle to serialize the data first.
也许你必须先使用像pickle这样的包来序列化数据。
import pickle
f1 = open("test.dat", "wb")
pickle.dump(d, f1)
f1.close()
Then load it back in:
然后重新加载它：
f2 = open("test.dat", "rb")
d2 = pickle.Unpickler(f2).load()
f2.close()
d2 == d
Returns True
返回真
