php 从 HTML 标签中删除样式属性
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Remove style attribute from HTML tags
提问by Martin Bean
I'm not too good with regular expressions, but with PHP I'm wanting to remove the styleattribute from HTML tags in a string that's coming back from TinyMCE.
我对正则表达式不太擅长，但是对于 PHP，我想style从 TinyMCE 返回的字符串中的 HTML 标记中删除该属性。
So change <p style="...">Text</p>to just vanilla <p>Test</p>.
所以<p style="...">Text</p>改为只是香草<p>Test</p>。
How would I achieve this with something like the preg_replace()function?
我将如何通过类似preg_replace()功能实现这一目标？
回答by Staffan N?teberg
The pragmatic regex (<[^>]+) style=".*?"will solve this problem in all reasonable cases. The part of the match that is not the first captured group should be removed, like this:
实用的正则表达式(<[^>]+) style=".*?"将在所有合理的情况下解决这个问题。应该删除不是第一个捕获组的匹配部分，如下所示：
$output = preg_replace('/(<[^>]+) style=".*?"/i', '', $input);
Match a <followed by one or more "not >" until we come to spaceand the the style="..."part. The /imakes it work even with STYLE="...". Replace this match with $1, which is the captured group. It will leave the tag as is, if the tag doesn't include style="...".
匹配 a<后跟一个或多个“not >”，直到我们来到space和style="..."部分。该/i更令其一起工作STYLE="..."。将此匹配替换为$1，即捕获的组。如果标签不包含style="...".
回答by Maerlyn
Something like this should work (untested code warning):
这样的事情应该可以工作（未经测试的代码警告）：
<?php
$html = '<p style="asd">qwe</p><br /><p class="qwe">qweqweqwe</p>';
$domd = new DOMDocument();
libxml_use_internal_errors(true);
$domd->loadHTML($html);
libxml_use_internal_errors(false);
$domx = new DOMXPath($domd);
$items = $domx->query("//p[@style]");
foreach($items as $item) {
$item->removeAttribute("style");
}
echo $domd->saveHTML();
回答by JaseC
I commented on @Mayerln 's function. It does work but DOMDocument really stuffs with encoding. Here's my simplehtmldom version
我评论了@Mayerln 的功能。它确实有效，但 DOMDocument 确实充满了编码。这是我的 simplehtmldom 版本
function stripAttributes($html,$attribs) {
$dom = new simple_html_dom();
$dom->load($html);
foreach($attribs as $attrib)
foreach($dom->find("*[$attrib]") as $e)
$e->$attrib = null;
$dom->load($dom->save());
return $dom->save();
}
回答by DreschF
I use this:
我用这个：
function strip_word_html($text, $allowed_tags = '<a><ul><li><b><i><sup><sub><em><strong><u><br><br/><br /><p><h2><h3><h4><h5><h6>')
{
mb_regex_encoding('UTF-8');
//replace MS special characters first
$search = array('/‘/u', '/’/u', '/“/u', '/”/u', '/—/u');
$replace = array('\'', '\'', '"', '"', '-');
$text = preg_replace($search, $replace, $text);
//make sure _all_ html entities are converted to the plain ascii equivalents - it appears
//in some MS headers, some html entities are encoded and some aren't
//$text = html_entity_decode($text, ENT_QUOTES, 'UTF-8');
//try to strip out any C style comments first, since these, embedded in html comments, seem to
//prevent strip_tags from removing html comments (MS Word introduced combination)
if(mb_stripos($text, '/*') !== FALSE){
$text = mb_eregi_replace('#/\*.*?\*/#s', '', $text, 'm');
}
//introduce a space into any arithmetic expressions that could be caught by strip_tags so that they won't be
//'<1' becomes '< 1'(note: somewhat application specific)
$text = preg_replace(array('/<([0-9]+)/'), array('< '), $text);
$text = strip_tags($text, $allowed_tags);
//eliminate extraneous whitespace from start and end of line, or anywhere there are two or more spaces, convert it to one
$text = preg_replace(array('/^\s\s+/', '/\s\s+$/', '/\s\s+/u'), array('', '', ' '), $text);
//strip out inline css and simplify style tags
$search = array('#<(strong|b)[^>]*>(.*?)</(strong|b)>#isu', '#<(em|i)[^>]*>(.*?)</(em|i)>#isu', '#<u[^>]*>(.*?)</u>#isu');
$replace = array('<b></b>', '<i></i>', '<u></u>');
$text = preg_replace($search, $replace, $text);
//on some of the ?newer MS Word exports, where you get conditionals of the form 'if gte mso 9', etc., it appears
//that whatever is in one of the html comments prevents strip_tags from eradicating the html comment that contains
//some MS Style Definitions - this last bit gets rid of any leftover comments */
$num_matches = preg_match_all("/\<!--/u", $text, $matches);
if($num_matches){
$text = preg_replace('/\<!--(.)*--\>/isu', '', $text);
}
$text = preg_replace('/(<[^>]+) style=".*?"/i', '', $text);
return $text;
}
回答by Lorenzo Marcon
Here you go:
干得好：
<?php
$html = '<p style="border: 1px solid red;">Test</p>';
echo preg_replace('/<p style="(.+?)">(.+?)<\/p>/i', "<p></p>", $html);
?>
By the way, as pointed out by others, regex are not suggested for this.
顺便说一句，正如其他人所指出的，不建议为此使用正则表达式。
回答by RafaSashi
In addition to Lorenzo Marcon's answer:
除了洛伦佐·马孔的回答：
Using preg_replaceto select everything except style attribute:
使用preg_replace来选择不同的样式属性的一切：
$html = preg_replace('/(<p.+?)style=".+?"(>.+?)/i', "", $html);
回答by Ashguard
I'm using such thing to clean-up the style='...' section out of tags with keeping of other attributes at the moment.
我正在使用这样的东西来清理标签中的 style='...' 部分，同时保留其他属性。
$output = preg_replace('/<([^>]+)(\sstyle=(?P<stq>["\'])(.*)\k<stq>)([^<]*)>/iUs', '<>', $input);
回答by Zmael
$html = preg_replace('/\sstyle=("|\').*?("|\')/i', '', $html);
For replacing all style="" with blank.
用于将所有 style="" 替换为空白。
回答by Daniel
You could handle it client side, the easiest would be with jQuery. Something like:
您可以在客户端处理它，最简单的方法是使用 jQuery。就像是：
$("#tinyMce p").removeAttr("style");
