PHP cURL，提取 XML 响应
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PHP cURL, extract an XML response
提问by Rakesh
I am invoking PHP cURL method on a server and the response is XML type. cURL is saving the output (after removing the tags) in a scalar type variable. Is there a way to store it in an object/hash/array so that it's easy to parse?
我在服务器上调用 PHP cURL 方法，响应是 XML 类型。cURL 将输出（删除标签后）保存在标量类型变量中。有没有办法将它存储在对象/哈希/数组中以便于解析？
回答by Alan Storm
<?php
function download_page($path){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$path);
curl_setopt($ch, CURLOPT_FAILONERROR,1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_TIMEOUT, 15);
$retValue = curl_exec($ch);
curl_close($ch);
return $retValue;
}
$sXML = download_page('http://alanstorm.com/atom');
$oXML = new SimpleXMLElement($sXML);
foreach($oXML->entry as $oEntry){
echo $oEntry->title . "\n";
}
回答by arkleyjoe
Just add header('Content-type: application/xml');before your echo of the XML response and you will see an XML page.
只需header('Content-type: application/xml');在 XML 响应的回显之前添加，您就会看到一个 XML 页面。
回答by limitcracker
Example:
例子：
<songs>
<song dateplayed="2011-07-24 19:40:26">
<title>I left my heart on Europa</title>
<artist>Ship of Nomads</artist>
</song>
<song dateplayed="2011-07-24 19:27:42">
<title>Oh Ganymede</title>
<artist>Beefachanga</artist>
</song>
<song dateplayed="2011-07-24 19:23:50">
<title>Kallichore</title>
<artist>Jewitt K. Sheppard</artist>
</song>
then:
然后：
<?php
$mysongs = simplexml_load_file('songs.xml');
echo $mysongs->song[0]->artist;
?>
Output on your browser: Ship of Nomads
浏览器上的输出：游牧之船
credits: http://blog.teamtreehouse.com/how-to-parse-xml-with-php5
学分：http: //blog.teamtreehouse.com/how-to-parse-xml-with-php5
回答by dusoft
no, CURL does not have anything with parsing XML, it does not know anything about the content returned. it serves as a proxy to get content. it's up to you what to do with it.
不，CURL 没有任何解析 XML 的功能，它对返回的内容一无所知。它充当获取内容的代理。这取决于你如何处理它。
use JSON if possible (and json_decode) - it's easier to work with, if not possible, use any XML library for parsin such as DOMXML: http://php.net/domxml
如果可能，使用 JSON（和 json_decode） - 如果不可能，使用任何 XML 库进行解析会更容易，例如 DOMXML：http://php.net/domxml
回答by Dipanjan
$sXML = download_page('http://alanstorm.com/atom');
// Comment This
// $oXML = new SimpleXMLElement($sXML);
// foreach($oXML->entry as $oEntry){
// echo $oEntry->title . "\n";
// }
// Use json encode
$xml = simplexml_load_string($sXML);
$json = json_encode($xml);
$arr = json_decode($json,true);
print_r($arr);
回答by Ganesh
simple load xml file ..
简单加载xml文件..
$xml = @simplexml_load_string($retValuet);
$status = (string)$xml->Status;
$operator_trans_id = (string)$xml->OPID;
$trns_id = (string)$xml->TID;
?>
?>
