C++ 将 cout 格式与表格的列对齐
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Align cout format as table's columns
提问by BobS
I'm pretty sure this is a simple question in regards to formatting but here's what I want to accomplish:
我很确定这是一个关于格式的简单问题，但这是我想要完成的：
I want to output data onto the screen using cout. I want to output this in the form of a table format. What I mean by this is the columns and rows should be properly aligned. Example:
我想使用 将数据输出到屏幕上cout。我想以表格格式的形式输出它。我的意思是列和行应该正确对齐。例子：
Test 1
Test2 2
Iamlongverylongblah 2
Etc 1
I am only concerned with the individual line so my line to output now (not working) is
我只关心单个行，所以我现在输出的行（不工作）是
cout << var1 << "\t\t" << var2 << endl;
cout << var1 << "\t\t" << var2 << endl;
Which gives me something like:
这给了我类似的东西：
Test 1
Test2 2
Iamlongverylongblah 2
Etc 1
回答by Eugene Yokota
setw.
#include <iostream>
#include <iomanip>
using namespace std;
int main () {
cout << setw(21) << left << "Test" << 1 << endl;
cout << setw(21) << left << "Test2" << 2 << endl;
cout << setw(21) << left << "Iamlongverylongblah" << 2 << endl;
cout << setw(21) << left << "Etc" << 1 << endl;
return 0;
}
回答by Leon Timmermans
I advise using Boost Format. Use something like this:
我建议使用Boost Format。使用这样的东西：
cout << format("%|1| %2%") % var1 % var2;
回答by Leon Timmermans
You must find the length of the longest string in the first column. Then you need to output each string in the first column in a field with the length being that of that longest string. This necessarily means you can't write anything until you've read each and every string.
您必须在第一列中找到最长字符串的长度。然后您需要输出字段中第一列中的每个字符串，其长度为该最长字符串的长度。这必然意味着在您阅读每个字符串之前您不能写任何东西。
回答by avishayhajbi
you can do it with
你可以用
string str = "somthing";
printf ("%10s",str);
printf ("%10s\n",str);
printf ("%10s",str);
printf ("%10s\n",str);
