在 C# 中将 JSON 文本加载到类对象中
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Load JSON text into class object in c#
提问by Vishwajeet
How can I convert the following Json Response to a C# object?
如何将以下 Json 响应转换为 C# 对象？
{ "err_code": "0", "org": "CGK", "des": "SIN", "flight_date": "20120719",
"schedule":
[
["W2-888","20120719","20120719","1200","1600","03h00m","737-200","0",[["K","9"],["F","9"],["L","9"],["M","9"],["N","9"],["P","9"],["C","9"],["O","9"]]],
["W2-999","20120719","20120719","1800","2000","01h00m","MD-83","0",[["K","9"],["L","9"],["M","9"],["N","9"]]]
] }
采纳答案by Shyju
First create a class to represent your json data.
首先创建一个类来表示您的 json 数据。
public class MyFlightDto
{
public string err_code { get; set; }
public string org { get; set; }
public string flight_date { get; set; }
// Fill the missing properties for your data
}
Using Newtonsoft JSON serializerto Deserialize a json stringto it's corresponding class object.
使用 Newtonsoft JSON 序列化程序将 json 字符串反序列化为其相应的类对象。
var jsonInput = "{ org:'myOrg',des:'hello'}";
MyFlightDto flight = Newtonsoft.Json.JsonConvert.DeserializeObject<MyFlightDto>(jsonInput);
Or Use JavaScriptSerializerto convert it to a class(not recommended as the newtonsoft json serializer seems to perform better).
或 JavaScriptSerializer用于将其转换为类（不推荐，因为 newtonsoft json 序列化程序似乎性能更好）。
string jsonInput="have your valid json input here"; //
JavaScriptSerializer jsonSerializer = new JavaScriptSerializer();
Customer objCustomer = jsonSerializer.Deserialize<Customer >(jsonInput)
Assuming you want to convert it to a Customerclasse's instance. Your class should looks similar to the JSONstructure (Properties)
假设您想将其转换为类Customer的实例。你的类应该看起来类似于JSON结构（属性）
回答by Talha
I recommend you to use JSON.NET. it is an open source library to serialize and deserialize your c# objects into json and Json objects into .net objects ...
我建议你使用JSON.NET. 它是一个开源库，用于将您的 c# 对象序列化和反序列化为 json 并将 Json 对象序列化和反序列化为 .net 对象......
Serialization Example:
序列化示例：
Product product = new Product();
product.Name = "Apple";
product.Expiry = new DateTime(2008, 12, 28);
product.Price = 3.99M;
product.Sizes = new string[] { "Small", "Medium", "Large" };
string json = JsonConvert.SerializeObject(product);
//{
// "Name": "Apple",
// "Expiry": new Date(1230422400000),
// "Price": 3.99,
// "Sizes": [
// "Small",
// "Medium",
// "Large"
// ]
//}
Product deserializedProduct = JsonConvert.DeserializeObject<Product>(json);
Performance Comparison To Other JSON serializiation Techniques
与其他 JSON 序列化技术的性能比较
回答by ff0000e2
This will take a json string and turn it into any class you specify
这将采用一个 json 字符串并将其转换为您指定的任何类
public static T ConvertJsonToClass<T>(this string json)
{
System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer();
return serializer.Deserialize<T>(json);
}
回答by Ole EH Dufour
To create a json class off a string, copy the string.
要从字符串创建 json 类，请复制该字符串。
In Visual Sudio, click Edit > Paste special > Paste Json as classes.
在 Visual Sudio 中，单击编辑 > 选择性粘贴 > 将 Json 粘贴为类。
回答by Islam
copy your Json and paste at textbox on http://json2csharp.com/and click on Generate button,
复制您的 Json 并粘贴到http://json2csharp.com/上的文本框，然后单击“生成”按钮，
A cs class will be generated use that cs file as below:
将使用该 cs 文件生成一个 cs 类，如下所示：
var generatedcsResponce = JsonConvert.DeserializeObject(yourJson);
var generatecsResponce = JsonConvert.DeserializeObject(yourJson);
where RootObject is the name of the generated cs file;
其中 RootObject 是生成的 cs 文件的名称；
