php 在 Cakephp 中通过 ajax 发送数据
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sending data via ajax in Cakephp
提问by hellosheikh
i am new to cakephp and trying to send data from ajax to my controller action.. i have a popup model in which there is a input box ..i want to grab that value and send to controller without page refresh
我是 cakephp 的新手，并试图将数据从 ajax 发送到我的控制器操作.. 我有一个弹出模型，其中有一个输入框..我想获取该值并发送到控制器而不刷新页面
here is my code ..
这是我的代码..
<a class="button anthracite-gradient" onclick="openPrompt()">submit </a>
my javascript
我的 JavaScript
function openPrompt()
{
var cancelled = true;
$.modal.prompt('Please enter a value:', function(value)
{
$.ajax({
type:"POST",
url:"/cakephp/controller/action/",
success : function(data) {
alert(value); //value right now is in this variable ... i want to send this variable value to the controller
},
error : function() {
alert("false");
}
});
}, function()
{
});
};
</script>
myController
我的控制器
public function action(){
if( $this->request->is('ajax') ) {
$new = $this->request->data;
echo "ok"
return;
}
}
i want to first get the value here and then send the response to may ajax request
我想首先在这里获取值，然后将响应发送到可能的 ajax 请求
回答by M Khalid Junaid
Its simple post the value to the controller and do what you want , in ajax request bind the value in data:{value_to_send:value}and get in controller
它简单地将值发布到控制器并执行您想要的操作，在 ajax 请求中绑定值data:{value_to_send:value}并进入控制器
function openPrompt()
{
var cancelled = true;
$.modal.prompt('Please enter a value:', function(value)
{
$.ajax({
type:"POST",
data:{value_to_send:value},
url:"/cakephp/controller/action/",
success : function(data) {
alert(data);// will alert "ok"
},
error : function() {
alert("false");
}
});
}, function()
{
});
};
</script>
public function action(){
if( $this->request->is('ajax') ) {
// echo $_POST['value_to_send'];
echo $value = $this->request->data('value_to_send');
//or debug($this->request->data);
echo "ok"
die();
}
}
For more see accessing-post-data
有关更多信息，请参阅访问后数据
回答by Sadee
I will give you some example. In my case, list out book list as a smart search while typing on text box.
我会给你一些例子。就我而言，在文本框中键入时，将图书列表列为智能搜索。
$( ".selectBook" ).each(function(){
$(this).keyup(function( event ) {
var tri = $(this).val();
var oPrnt = $(this).parents('.smartsearch');
var str = '';
if(tri.length > 2){
$.ajax({
type: "POST",
url: "/utility/getbooks/",
data: JSON.stringify({string: tri, activeonly:false}),
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
$.each(data, function(key, val) {
str += '<li id="a'+key+'" term="'+val+'" data-did="'+key+'">'+val+'</li>';
});
oPrnt.find("ul.result").html(str);
},
error: function (errormessage) {
oPrnt.find("ul.result").html('<li><b>No Results</b></li>');
}
});
oPrnt.find("ul.result").slideDown(100);
}
});
});
And in the controller, action (getbooks Action in UtilityController in my case)
在控制器中，动作（在我的例子中 UtilityController 中的 getbooks 动作）
public function getbooks($string = '', $activeonly = true){
$this->autoRender = false;
if( $this->request->is('ajax') ) {
$data = $this->request->input('json_decode');
$string = $data->string;
$activeonly = $data->activeonly;
}
$aReturn = array();
// ... fetch books data from DB goes here...
$aResult = $this->Book->fetch('list');
foreach($aResult as $r){
if(isset($r['bookname'])){
$aReturn[$r['id']] = $r['bookname'];
}
}
return json_encode($aReturn);
}
